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Aloiza [94]
4 years ago
8

What transfers the electrons generated during the light cycle to co2 during the calvin cycle?

Chemistry
1 answer:
natta225 [31]4 years ago
6 0

Answer:

The correct answer is NADPH.

Explanation:

It takes 6 molecules of CO2 to generate one molecule of glucose. Each of the CO2 molecules is attached to a RuBP-acceptor molecule, which is then divided into two 3-phosphoglycerate molecules.

The ATP produced during the light reactions of photosynthesis yields phosphate groups to these molecules, resulting in 1,3-diphosphoglycerate. Simultaneously, NADPH yields electrons to these three-carbon molecules, creating glyceraldehyde-3-phosphate molecules. Glyceraldehyde-3-phosphate is used to make the sugar from 6 glucose carbons. Another part of the glyceraldehyde-3-phosphate is used together with an ATP molecule, to generate the CO2 acceptor ribulose-1,5-bisphosphate and start the cycle again.

Have a nice day!

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COLLEGE CHEMISTRY 35 POINTS
Sati [7]

6.81% is the percent yield when 12 g of CO2 are formed experimentally from the reaction of 0.5 moles of C8H18 reacting with excess oxygen.

Explanation:

Data given:

mass of carbon dioxide formed = 12 grams (actual yield)

atomic mass of CO2 = 44.01 grams/mole

moles of C_{8} H_{18} = 0.5

Balanced chemical reaction:

2 C_{8} H_{18} + 25 O_{2} ⇒ 16 CO_{2} + 18 H_{2} _O{}

number of moles of carbon dioxide given is

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles= \frac{12}{44}

number of moles of carbon dioxide gas = 0.27 moles

from the reaction 2 moles of C_{8} H_{18} reacts to produce 16 moles of CO_{2}

So, when 0.5 moles reacted it produces x moles

\frac{16}{2} = \frac{x}{0.5}

x = 4

4 moles of carbon dioxide formed, mass from it will give theoretical yield.

mass  = number of moles x molar mass

mass = 4 x 44.01

        = 176.04 grams

percent yield =\frac{actual yield}{theoretical yield} x 100

percent yield = \frac{12}{176.04} x 100

     percent yield  = 6.81 %

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