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r-ruslan [8.4K]
3 years ago
10

**WILL MAKE BRAINLIEST AND LEAVE GOOD REVIEWS, PLEASE HELP ME OUT I HAVE 5 MINS LEFTT*****

Mathematics
1 answer:
notsponge [240]3 years ago
7 0

Answer : we can make only one angle with this  because it is necessary to have AB as a base line because the given angle is of <B means we have to make angle at point B  . if we take  AC as a base line we can not draw angle because we have to make angle at point B so .

. draw a line of AB =7.6

.draw <ABC of 50 degree

.then from point A draw an arc of 5.4 cm at point c

join point A to point C



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What’s the value of x <br> A- 86.5<br> B- 43.25<br> C- 133.25<br> D- 46.75
DiKsa [7]
133.25 is the awnser for this question
5 0
3 years ago
Read 2 more answers
Need help with this
netineya [11]
The answer to your question is C.
3 0
3 years ago
Suppose that a certain college class contains students. Of these, are juniors, are mathematics majors, and are neither. A studen
ipn [44]

Answer:

<h2>2/5</h2>

Step-by-step explanation:

The question is not correctly outlined, here is the correct question

<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>

Given data

Total students in class= 35 students

Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so

|M ∪ N|= 35-12= 23

|M∩N|=  |M|+N- |MUN|= 17+20-23

           =37-23=14

So the probability that a random student is both a junior and social science major is

=P(M∩N)= 14/35

=2/5

7 0
2 years ago
A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

  $E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
3 years ago
If the perimeters of each shape are equal, which equation can be used to find the value of x?
Brums [2.3K]

Answer:

(x+2) + x + (x+4) = 2(1/2) + 2(x+3)

Step-by-step explanation:

They are equal to each other and the rectangle has 2x more perimeter

The triangle would be divided in half from that rectangle.

Sorry If this is confusing I am not very good at explaining things.

4 0
3 years ago
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