Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.
Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."
It means, the volume is decreased if the pressure is increased and vice versa.
Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:
Where, is initial pressure and is final pressure. Similarly, is initial volume and is final volume.
Let's plug in the values in the equation:
(537 torr)(5.30 L) = (255 torr)()
= 11.2 L
So, the new volume of the container needs to be 11.2 L.
First you need to calculate the number of moles of aluminium and copper chloride.
number of moles = mass / molecular weight
moles of Al = 512 / 27 = 19 moles
moles of CuCl = 1147 / 99 = 11.6 moles
From the reaction you see that:
if 2 moles of Al will react with 3 moles of CuCl
then 19 moles of Al will react with X moles of CuCl
X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.
The ph of the solution would be 8
Answer:
950mL
Explanation:
The following were Data were obtained from the question:
Initial volume (V1) = 100mL
Initial pressure (P1) = stp = 760mmHg
Final pressure (P2) = 80mmHg
Final volume (V2) =..?
The final volume of the gas can be obtained by using the Boyle's law equation as follow:
P1V1 = P2V2
760 x 100 = 80 x V2
Divide both side by 80
V2 = (760 x 100) /80
V2 = 950mL
Therefore, the new volume of the gas is 950mL
Answer:
0 %
Explanation:
As we know 10.81 is the average atomic mass of boron which can not be contained by a single boron atom. Therefore, when isolated, a single boron atom will weight either 10 amu for ¹⁰B and 11 amu for ¹¹B respectively.
The average atomic mass is calculated as;
Atomic Mass of ¹⁰B = 10
Atomic Mass of ¹¹B = 11
Natural Abundance of ¹⁰B = 20 %
Natural Abundance of ¹¹B = 80 %
So,
Average Atomic Mass = (10 × 0.2) + (11 × 0.8)
Average Atomic Mass = 2 + 8.8
Average Atomic Mass = 10.8