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lyudmila [28]
4 years ago
11

Pls answer the question

Chemistry
2 answers:
Artyom0805 [142]4 years ago
8 0

Answer:

1) fractional distillation

3) centrifugation

yanalaym [24]4 years ago
8 0

Answer:

1. Fractional distillation

2. Evaporation

3. Centrifuge

4. Fractional distillation

5. Electrophoresis

Explanation:

Two miscible (easily mixing fluids) are separated according to the difference in the boiling points. Thus, fractional distillation is used. This uses the phase equilibria between the liquid entering the plate and the vapor leaving the distillation plate.

Sometimes a reflux is needed to separate the substances and produce a pure substance and preserve heat.

Evaporation will work for a salt and water solution. The water is simply boiled off.  What remains is the NaNO_{3}

Lastly, proteins in blood are separated by gravity in a centrifuge.

Electrophoresis separates amino acids according to their charges.

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Formula for the elements if they were to bong together. <br><br> Iodine and Bromine
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I(Br)

Explanation:

You will be combining one iodine atom with one bromine atom.

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Isotopes that decay with a nuclear break-up and emit a significant amount of energy are said to be ________.
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Answer to this is Radioactive isotopes.

Isotopes are the species of the same element having different atomic masses that means the number of protons remains the same but number of neutrons do differ. For example _{1}^{2}\textrm{H} and _{1}^{3}\textrm{H} are the two isotopes of Hydrogen (_{1}^{1}\textrm{H} ).

Radioactive isotopes are the isotopes which release some kind of energy in the form of alpha particles, beta particles or gamma radiation. Examples of each of the decay processes are :

Alpha Decay: In this decay one alpha particle having atomic mass 4 and atomic number 2 or we can say a He molecule will come out. _{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_{2}^{4}\alpha

Beta Decay: In this decay a \beta particle is emitted increasing the atomic number of the reactant by 1 unit.

_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^{0}\beta

Gamma Radiation: In this type of reaction only radiation is emitted out which does not change the original molecule.

_{Z}^{A}\textrm{X}\rightarrow _{Z}^{A}\textrm{X}+\gamma\text{ radiation}

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An atom has the following electron configuration.
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Three samples of the same metal are weighed and their masses are found to be 44.40 g, 40.58 g, and 38.35 g. The corresponding vo
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The density of a material is the mass of the material per unit volume. Here the weight of the same metal is 44.40g, 40.58g and 38.35g having volume 4.8 mL, 4.7 mL and 4.2 mL respectively. Thus the density of the metal as per the given data are, \frac{44.40}{4.8} = 9.25g/mL, \frac{40.58}{4.7} = 8.634g/mL and \frac{38.35}{4.2} = 9.130g/mL respectively.

The equation of the standard deviation is √{∑(x  - \frac{}{x})÷N}

Now the mean of the density is {(9.25 + 8.634 + 9.130)/3} = 9.004 g/mL.

The difference of the density of the 1st metal sample (9.25-9.004) = 0.246 g/mL. Squaring the value = 0.060.

The difference of the density of the 2nd metal sample (9.004-8.634) =0.37 g/mL. Squaring the value = 0.136.

The difference of the density of the 3rd metal sample (9.130-9.004) = 0.126 g/mL. Squaring the value 0.015.

The total value of the squared digits = (0.060 + 0.136 + 0.015) = 0.211. By dividing the digit by 3 we get, 0.070. The standard deviation will be \sqrt{0.070}=0.265. Thus the standard deviation of the density value is 0.265g/mL.  

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