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4vir4ik [10]
2 years ago
5

Pls help me also pls have the correct answer

Chemistry
2 answers:
Mademuasel [1]2 years ago
6 0

Answer:

Explanation:cccccccccccccccccccccccccccccccc

Ann [662]2 years ago
4 0

Answer:

       

Explanation:

       

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Compare and contrast 10kg of melting ice and 1kg of freezing water address temperature heat flow thermal energy what is the simp
iris [78.8K]

Answer:

10 kg of ice will require more energy than the released when 1 kg of water is frozen because the heat of phase transition increases as the mass increases.

Explanation:

Hello!

In this case, since the melting phase transition occurs when the solid goes to liquid and the freezing one when the liquid goes to solid, we can infer that melting is a process which requires energy to separate the molecules and freezing is a process that releases energy to gather the molecules.

Moreover, since the required energy to melt 1 g of ice is 334 J and the released energy when 1 g of water is frozen to ice is the same 334 J, if we want to melt 10 kg of ice, a higher amount of energy well be required in comparison to the released energy when 1 kg of water freezes, which is about 334000 J for the melting of those 10 kg of ice and only 334 J for the freezing of that 1 kg of water.

Best regards!

7 0
3 years ago
Part b an "empty" container is not really empty if it contains air. how may moles of nitrogen are in an "empty" two-liter cola b
Sedbober [7]
<span>6.38x10^-2 moles
       First, let's determine how many moles of gas particles are in the two-liter container. The molar volume for 1 mole at 25C and 1 atmosphere is 24.465 liters/mole. So
   2 L / 24.465 L/mol = 0.081749438 mol
       Now air doesn't just consist of nitrogen. It also has oxygen, carbon dioxide, argon, water vapor, etc. and the total number of moles includes all of those other gasses. So let's multiply by the percentage of nitrogen in the atmosphere which is 78%
    0.081749438 mol * 0.78 = 0.063764562 mol.
        Rounding to 3 significant figures gives 6.38x10^-2 moles</span>
4 0
3 years ago
Read 2 more answers
A. Explain, in terms of particles, why NaCl(s) does not conduct electricity.
yawa3891 [41]

Answer:

Ionic bonds hold charged particles in solid NaCl together, such that they are unable to move or conduct electricity.

Explanation:

Consider an electric current that flows through a conductor: charge moves in a uniform direction from one end of the conductor towards the other.

Thus, there are two conditions for a substance to conduct electricity:

  • The substance shall contain charged particles, and
  • These charged particles shall be free to move across the substance.

A conductor of electricity shall meet both requirements.

Now, consider the structure of solid NaCl \rm NaCl\;(s). NaCl is an ionic compound. It contains an ocean of oppositely charged ions:

  • Positive \rm Na^{+} ions, and
  • Negative \rm Cl^{-} ions.

Ions carry charge. Thus, solid NaCl contains charged particles and satisfies the first condition.

Inside solid NaCl \rm NaCl\;(s), electrostatic attractions ("ionic bonds") between the oppositely charged ions hold these ions in rigid ionic lattices. These ions are unable to move relative to each other. As a result, they cannot flow through the solid to conduct electricity. Under solid state, NaCl is unable to satisfy the second condition.

As a side note, melting NaCl into a liquid breaks the ionic bonds and free the ions from the lattice. Liquid NaCl is a conductor of electricity.

8 0
2 years ago
Which statements describe seismic waves? Select three options.
Alenkasestr [34]

Answer:

A, C, E

Explanation:

8 0
2 years ago
Read 2 more answers
38. Identify the most important types of interparticle forces pres
zhannawk [14.2K]

Answer: im thinking its gonna be d.C2H6 and also

the explanation is on the research i had did before i had answered this question so i really hope this help :)

Explanation:

Ar = van de waals forces or london forces

C

H

4

= van de waals forces or london forces

HCl=permanent dipole-dipole interactions

CO = permanent dipole-dipole interactions

HF = hydrogen bonding

N

a

N

O

3

= permanent dipole-dipole interactions

C

a

C

l

2

= van de waals forces or london forces

4 0
2 years ago
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