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3 years ago

8

a recipe calls for 2 2/4 cups of raisins,but Julie only has a 1/4 measuring cup. how many 1/4 cups does Julie need to measure ou

t 2 and 2/4 cups of raisins

1 answer:

kozerog [31]3 years ago

7 0

Answer:

10

Step-by-step explanation:

Divide 2 2/4 cups of raisins by 1/4 cup:

10 cups

-------------

4

=============

1 cup

--------

4

Invert the divisor and then multiply:

10 cups 4

------------- · ---------- = 10

4 1 cup

Julie must measure out 10 of these 1/4-cup measures (of raisins).

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A rectangular floor of area 360 m2 is going to be tiled. Each tile is rectangular, and has an area of 240 cm2. An exact number o

scoray [572]

Answer:

1500

Step-by-step explanation:

The area of the regtangular floor is 360m². The floor is going to be retired with tiles having area of 240cm² . We need to find the number of times . Therefore ,

$\implies 360m^2 = 360 \times 10^4 \ cm^2$

And , the number of tiles required will be ,

$\implies n =\dfrac{Area \ of \ floor}{Area \ of \ a \ tile }\\\\\implies n =\dfrac{ 360 \times 10^4 \ cm^2}{240 cm^2} \\\\\implies \underline{\underline{ n = 1,500 }}$

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>1</u><u>5</u><u>0</u><u>0</u><u> </u><u>.</u>

4 0

3 years ago

Solve B=1/4m(s+z) for s

ElenaW [278]

Answer:

$s = \frac{-mz+4B}{m}$

Step-by-step explanation:

Step 1: Distribute.

$B = \frac{1}{4}m * s + \frac{1}{4}m * z$
$B = \frac{1}{4}ms + \frac{1}{4}mz$
$\frac{1}{4}ms + \frac{1}{4}mz = B$

Step 2: Subtract 1/4(mz) from both sides.

$\frac{1}{4}ms + \frac{1}{4}mz - \frac{1}{4}mz = B - \frac{1}{4}mz$
$\frac{1}{4}ms = -\frac{1}{4}mz + B$

Step 3: Divide both sides by m/4.

$\frac{1}{4}ms/\frac{m}{4}=(\frac{-1}{4}mz + B)/\frac{m}{4}$
$s = \frac{-mz+4B}{m}$

6 0

3 years ago

A company that makes cartons finds that the probability of producing a carton with a puncture is 0.04, the probability that a ca

Over [174]

Answer:

a) C. No, a carton can have a puncture and a smashed corner.

b) The probability that a carton has a puncture or a smashed corner is P(X ∪ Y) = 0.104.

Step-by-step explanation:

To be mutually exclusive, the probability of the two events happening at the same time should be 0. But the probability that a carton has a puncture and has a smashed corner is 0.004 and not 0.

Then, we can conclude the events "selecting a carton with a puncture" and "selecting a carton with a smashed corner" are not mutually exclusive.

The answer is "C. No, a carton can have a puncture and a smashed corner."

We can calculate the probability that the carton has a puncture <em>or </em>has a smashed comer simply by adding the probability of each event:

$P(X\cup Y)=P(X)+P(Y)=0.1+0.04=0.104$

P(X ∪ Y): probability that a carton has a puncture or a smashed corner.

5 0

4 years ago

Cassandra's Cogs advertises on its website that 90% of customer orders are received within three working days. They performed an

11111nata11111 [884]

Using the Central Limit Theorem, we have that:

a) Yes, it can be used, as np > 10 and n(1 - p) > 10.

b) There is a 0.0475 = 4.75% probability that the proportion in the random sample of 100 orders is the same as the proportion found in the audit sample or less.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

For the sample, we have that:

np = 85 > 10.

n(1 - p) = 15 > 10.

Hence the normal approximation can be used.

As for part B, if we have p = 0.9 and n = 100, the mean and the standard error are given by:

$\mu = p = 0.9$ .

$s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.9(0.1)}{100}} = 0.03$

The probability of a sample proportion of 85% of less is the <u>p-value of Z when X = 0.85</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.85 - 0.9}{0.03}$

Z = -1.67

Z = -1.67 has a p-value of 0.0475.

There is a 0.0475 = 4.75% probability that the proportion in the random sample of 100 orders is the same as the proportion found in the audit sample or less.

More can be learned about the Central Limit Theorem at brainly.com/question/24663213

#SPJ1

8 0

2 years ago

Y=1/3-1/2x what is the slope and y-intercept

MrMuchimi

Answer:

slope is -1/2 and y- intercept is 1/3

Step-by-step explanation:

use y=mx+b

m=slope

b= y-intercept

rearrange your equation

y=1/3-1/2x

y=-1/2x+1/3

4 0

3 years ago