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Varvara68 [4.7K]

3 years ago

12

The density of Jell-O® is 1.56 g/cm3. A suite in a dorm can hold 6.35 × 107 g of Jell-O®. What is the volume of the suite in ft3

? [2.54 cm = 1 in, 12 in = 1 ft]

1 answer:

qwelly [4]3 years ago

8 0

Put in the values into density formula, convert cm^3 to ft^3 and write final solution.

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lions [1.4K]

I would say 4 but you can figure it out or if you have a parent near by to

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3 years ago

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A speed time graph shows that a car moves at 20 m/s for 15s. The car's speed steadily decreases until it comes to a stop at 40s.

ladessa [460]

0s to 15s: constant speed/zero acceleration
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4 0

3 years ago

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scZoUnD [109]

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3 0

3 years ago

Write the ground-state electron configuration for the chloride ion.You may write either the full or condensed electron configura

dalvyx [7]

Answer:

$1s^22s^22p^63s^23p^6$

Explanation:

Chlorine is the element of group 17 and third period. The atomic number of chlorine is 17 and the symbol of the element is Cl.

The electronic configuration of the element chlorine is:-

$1s^22s^22p^63s^23p^5$

Chloride ion is formed when chlorine atom gain one more electron. So, the ground-state electron configuration for the chloride ion is:-

$1s^22s^22p^63s^23p^6$

8 0

3 years ago

A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C

Mamont248 [21]

Answer:

$T_{eq}=23.85^oC$

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

$\Delta H_{Cu}=-\Delta H_{H_2O}$

Therefore the equilibrium temperature shows up as:

$m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\$

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

$T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC$

Best regards.

6 0

3 years ago

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