Hydrochloric is added to a beaker containing a piece of zinc. As a result, zinc chloride is formed and hydrogen gas is released.
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Answer:
Mass percentage of gold : 33.35%
Mass percentage of silver: 62.80%
Mass percentage of copper : 3.85%
Explanation:
Where : N = Number of atoms
n = moles
= Avogadro number
Let the total atoms present in the alloy be 100.
Atom percentage of silver = 44.9%
Atoms of of silver = 44.9% of 100 atoms = 44.9
Atomic weight of silver = 107.87 g/mol
Mass of 44.9 silver atoms = 107.87 g/mol × 44.9 = 4,843.363 g/mol
Atom percentage of gold= 46.3%
Atoms of of gold = 46.3% of 100 atoms = 46.3
Atomic weight of gold = 196.97 g/mol
Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol
Atom percentage of copper = 8.8 %
Atoms of of copper = 8.8% of 100 atoms = 8.8
Atomic weight of copper = 63.55 g/mol
Mass of 44.9 copper atoms = 63.55 g/mol × 8.8 = 559.24 g/mol
Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol
Mass percentage of gold :
Mass percentage of silver:
Mass percentage of copper :
The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d
Rydberg's formula :
,
where λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from to
and
= 109677 is the Rydberg Constant. Here
and
represents the transitions.
(a) =2 to
= infinity
= 109677/4 [since 1/infinity = 0] Therefore,
= 4 / 109677 = 0.00003647 m
(b) =4 to
= 20
= 6580.62
Therefore, = 1 / 6580.62 = 0.000152 m
(c) =3 to
= 10
= 11089.56
Therefore, = 1 / 11089.56 = 0.00009 m
(d) =2 to
= 1
= - 82257.75
Therefore, = 1 /82257.75 = - 0.0000121 m
[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]
So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.
Learn more about the Rydberg's formula athttps://brainly.com/question/14649374
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