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Assoli18 [71]
4 years ago
11

Changes in the environment that cause an organism to respond are called?

Chemistry
2 answers:
Fiesta28 [93]4 years ago
8 0

Answer:

Anything in the environment that causes a change is called a stimulus.

Explanation:

Organisms react to many stimuli, including light, temperature, odor, sound, gravity, heat, water, and pressure. The ability of living things to react to stimuli is known as irritability.

slega [8]4 years ago
6 0

Answer:

Anything in the environment that causes a change is called a stimulus.

Explanation:

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A/An ______ bond occurs when 2 atoms share electrons.
allsm [11]

Answer:

convalent???????

Explanation:

sowwy if it wrong

8 0
3 years ago
calculate the mass required to prepare 2.5 L of 1.0 M NaOH solution. Given that the molar mass for NaOH is 40 g/mol.
Helen [10]

Answer:

The required mass to prepare 2.5 L of 1.0 M NaOH solution is 100 g

Explanation:

We do this by preparing the equation:

Mass = concentration (mol/L) x volume (L) x Molar mass

Mass = 1.0 M x 2.5 L x 40 g/mol

Mass = 100 g

3 0
3 years ago
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Why do we have rain........................
VladimirAG [237]

Answer:

to watered our source of food

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6 0
3 years ago
What is meant by a “ chain reaction “ ?
lilavasa [31]

Answer:

a chemical reaction or other process in which the products themselves promote or spread the reaction, which under certain conditions may accelerate dramatically.

Explanation:

the self-sustaining fission reaction spread by neutrons which occurs in nuclear reactors and bombs.

a series of events, each caused by the previous one.

5 0
3 years ago
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At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction:
Butoxors [25]

<u>Answer:</u> The equilibrium concentration of ICl is 0.27 M

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.45 moles

Initial moles of chlorine gas = 0.45 moles

Volume of the flask = 2.0 L

The molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

Initial concentration of iodine gas = \frac{0.45}{2}=0.225M

Initial concentration of chlorine gas = \frac{0.45}{2}=0.225M

For the given chemical equation:

2ICl(g)\rightarrow I_2(g)+Cl_2(g);K_c=0.11

As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.

The chemical equation becomes:

                      I_2(g)+Cl_2(g)\rightarrow 2ICl(g);K_c=\frac{1}{0.11}=9.091

<u>Initial:</u>         0.225      0.225

<u>At eqllm:</u>   0.225-x    0.225-x     2x

The expression of K_c for above equation follows:

K_c=\frac{[ICl]^2}{[Cl_2][I_2]}

Putting values in above equation, we get:

9.091=\frac{(2x)^2}{(0.225-x)\times (0.225-x)}\\\\x=0.135,0.668

Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration

So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M

Hence, the equilibrium concentration of ICl is 0.27 M

6 0
3 years ago
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