(i) Volume of point Naon to reach equivalence. = 24.0mL
(ii) volume of Naon used to reach 50% T = 12.0mL
(iii) PKA of an unknown acid = 4.8
(iv) moles of acid reacted = moles of NaOH
man/molar mass = 0.269g/MW = Molarity x volume
0.269g/MW = 0.09560 mol/K x 24. 0×/K
MW = 0.269g/0.09560 mol x 24.0x
MW = 117.24g mol-1
(v) In matching the given table of molar masses. with obtained man matches with that, we get that it of hexanoic acid.
<u>unknown acid = hexanoic acid</u>
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Titration is used to determine the amount of a substance present by reacting it with a known amount of another substance. For example, the molar mass of an acid can be found by titrating it with a base solution of known concentration. Your unknown solid is an acid. This is dissolved in water and phenolphthalein indicator is added and titrated to the endpoint with standard NaOH solution. Unknown acids are monobasic. There is only one acidic hydrogen per molecule.
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Answer:
The moon revolves around the Earth once every 29.5 days
Explanation:
So around 30 days.
<span>1. </span>To solve this we assume
that the gas is an ideal gas. Then, we can use the ideal gas equation which is
expressed as PV = nRT. At a constant temperature and number of moles of the gas
the product of PV is equal to some constant. At another set of condition of
temperature, the constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 x V1 / P2
V2 = 104.1 x 478 / 88.2
<span> V2 =564.17 cm^3</span>
The ammonium iodide solution is converted into a buffer by the addition of ammonia (NH₃).
<h3>What is a buffer solution?</h3>
- A solution which is formed by the addition of weak acid and its conjugate base or weak base and its conjugate acid.
- They resist a change in pH of the solution when an acid or alkali added to them.
<h3>Which is to be added to the given solution to convert it into a buffer?</h3>
The given solution contains 0.21 M ammonium iodide (NH₄I). This is a salt of a weak base(NH₃) and a strong acid(HI).
NH₄I(s) → NH₃(g) + HI(g)
Where the salt is ionic. So, in aqueous solution it dissociates into NH₄⁺ and I⁻
The ammonium ion NH₄⁺ is the conjugate acid of the weak base NH₃.
So, the mixture of this weak base NH₃ and its conjugate acid NH₄⁺ converts the solution into a buffer.
Therefore, one liter of the given solution could be converted into a buffer by the addition of a weak base NH₃.
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If the size is bigger than the em it is weaker <span />