Answer:
1561.84 MPa
Explanation:
L=20 cm
d1=0.21 cm
d2=0.25 cm
F=5500 N
a) σ= F/A1= 5000/(π/4×(0.0025)^2)= 1018.5916 MPa
lateral strain= Δd/d1= (0.0021-0.0025)/0.0025= -0.16
longitudinal strain (ε_l)= -lateral strain/ν = -(-0.16)/0.3
(assuming a poisson's ration of 0.3)
ε_l =0.16/0.3 = 0.5333
b) σ_true= σ(1+ ε_l)= 1018.5916( 1+0.5333)
σ_true = 1561.84 MPa
ε_true = ln( 1+ε_l)= ln(1+0.5333)
ε_true= 0.4274222
The engineering stress on the rod when it is loaded with a 5500 N weight is 1561.84 MPa.
Ability to recognize words and understand vocabulary
Answer: Option 2.
<u>Explanation:</u>
Reading comprehension is the capacity to process content, comprehend its significance, and to incorporate with what the peruser definitely knows. Capacity to grasp content is affected by perusers' aptitudes and their capacity to process data.
For the students reading comprehension problems frequently include troubles in perceiving and suitably applying foundation information, poor disentangling and word acknowledgment abilities, restricted jargon information, immature understanding familiarity, a not exactly key way to deal with cognizance.
solution from c hegg. hope it helps. see photos explanation
Answer:
How must used oil storage containers be marked? Containers and aboveground tanks used to store used oil at generator facilities must be labeled or marked clearly with the words “Used Oil" (40 CFR Section 279.22(c)).
Explanation:
i think it will help you
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I had a couple of answers for this, but when I checked nothing
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