Ask question

Ask question

All categories

3 years ago

8

An individual is planning to take an 800-mile trip between two large cities. Three pos-sibilities exist: air, rail, or auto. The

person is willing to pay $25 for every hour savedin making the trip. The trip by air costs $600 and travel time is 8 hours, by rail the costis $450 and travel time is 16 hours, and by auto the cost is $200 and travel time is 20 hours.
(a) Which mode is the best choice?
(b) What factors other than cost might influence the decision regarding which mode to use?

1 answer:

vagabundo [1.1K]3 years ago

8 0

Answer:

1. Auto is the best mode since it is the cheapest

2. Safety, reliability, convenience should be considered

Explanation:

1.

This person is willing to pay $25 per hour.

To get the mode, which is the best choice I used this formula

Cost of trip + 25T

T = time or number of hours

By air travel

Cost = $600, T = 8 hours

600+25(8)

= 600+200

= 800 dollars

By rail,

Cost = $450

T = 16 hours

450+25(16)

= 450+400

= 850 dollars

By auto,

Cost = $200

T = 20 hours

200+25(20)

= 200+500

= 700 dollars

From these calculations the cost of Traveling by auto is the cheapest so it is the best mode.

2. Other factors to consider when choosing an alternative mode of transport

A. Safety: this transportation material should be able to get to it's destination without any form of damages happening

B. Reliability: the material should be able to fulfill it's requirements

C. Convenience: in terms of availability per day and also the frequency of traveling time

You might be interested in

Help please i will give brainlist

vlada-n [284]

Answer:

Open Circuit

Explanation:

Because the circuit isnt closed, the current wont flow

5 0

2 years ago

Read 2 more answers

Silicon chips are used primarily in ?

VMariaS [17]

Answer:

4th generation computers

5 0

2 years ago

What is code in Arduino to turn led on and off

11Alexandr11 [23.1K]

here's your answer..

4 0

3 years ago

Consider the circuit below where R1 = R4 = 5 Ohms, R2 = R3 = 10 Ohms, Vs1 = 9V, and Vs2 = 6V. Use superposition to solve for the

VladimirAG [237]

Answer:

The value of v2 in each case is:

A) V2=3v for only Vs1

B) V2=2v for only Vs2

C) V2=5v for both Vs1 and Vs2

Explanation:

In the attached graphic we draw the currents in the circuit. If we consider only one of the batteries, we can consider the other shorted.

Also, what the problem asks is the value V2 in each case, where:

$V_2=I_2R_2=V_{ab}$

If we use superposition, we passivate a battery and consider the circuit affected only by the other battery.

In the first case we can use an equivalent resistance between R2 and R3:

$V_{ab}'=I_1'R_{2||3}=I_1'\cdot(\frac{1}{R_2}+\frac{1}{R_3})^{-1}$

And

$V_{S1}-I_1'R_1-I_1'R_4-I_1'R_{2||3}=0 \rightarrow I_1'=0.6A$

$V_{ab}'=I_1'R_{2||3}=3V=V_{2}'$

In the second case we can use an equivalent resistance between R2 and (R1+R4):

$V_{ab}''=I_3'R_{2||1-4}=I_3'\cdot(\frac{1}{R_2}+\frac{1}{R_1+R_4})^{-1}$

And

$V_{S2}-I_3'R_3-I_3'R_{2||1-4}=0 \rightarrow I_3'=0.4A$

$V_{ab}''=I_3'R_{2||1-4}=2V$

If we consider both batteries:

$V_2=I_2R_2=V_{ab}=V_{ab}'+V_{ab}''=5V$

7 0

4 years ago

2. (Problem 4.60 on main book, diameters different) Water flows steadily through a fire hose and nozzle. The hose is 35 mm diame

Viefleur [7K]

Answer:

coupling is in tension

Force = -244.81 N

Explanation:

Diameter of Hose ( D1 ) = 35 mm

Diameter of nozzle ( D2 ) = 25 mm

water gage pressure in hose = 510 kPa

stream leaving the nozzle is uniform

exit speed and pressure = 32 m/s and atmospheric

<u>Determine the force transmitted by the coupling between the nozzle and hose </u>

attached below is the remaining part of the detailed solution

Inlet velocity ( V1 ) = V2 ( D2/D1 )^2

= 32 ( 25 / 35 )^2

= 16.33 m/s

4 0

3 years ago