Mang Tisoy bought two bags of onion from the market. One bag weighed 8 kg

City A and city B are located at the same latitude and elevation. City A is a coastal city, and city B is located far inland. A

jenyasd209 [6]

Answer:

Option 4

Explanation:

8 0

3 years ago

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The data shows that recently the size of the raccoon population decreased. How will the decrease in the raccoon population affec

LenaWriter [7]

Answer: Increase in the population of lower organisms.

Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.

They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.

Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.

3 0

3 years ago

In an analog addressable system, the determination of the alarm state is performed by the _____?

Nostrana [21]

Answer:

Control panel

Explanation:

The Control Panel is a component of Microsoft Windows which provides the ability to view and change system settings. It consists of a set simple computer programs (applets) that include adding or removing hardware and software, controlling user accounts, changing accessibility options, and accessing networking settings.

6 0

3 years ago

2. Using an RLC circuit to design a band-reject filter, with the two cut off frequencies 40k and 90k Hz. Design the values of R,

nadya68 [22]

Answer:

C = 59.17 nF

Q = 2.6

Explanation:

given data

frequencies = 40k Hz

frequencies = 90k Hz

solution

we take here R, L C take in series

so cut off frequency is express as

Wc1 = $-\frac{R}{2L}+ \sqrt{(\frac{R}{2L})^2+\frac{1}{LC}}$ = 40000

wc2 = $\frac{R}{2L}+ \sqrt{(\frac{R}{2L})^2+\frac{1}{LC}}$ = 90000

so here

wc2 - wc1 will be

wc2 - wc1 = 90000 - 40000 = 50000

so

$\frac{R}{L}$ = 50000

we consider here R is 500

so L = $\frac{500}{50000}$

L = 10 m H

and here total cut off frequency is

total cut off frequency = 40000 + 90000 = 130000

so capacitance will be

capacitance C is = $\frac{1}{10\times 10^{-3}\times 130000^2}$

so C = 59.17 nF

quality factor Q will be

Q = $\frac{130000}{50000}$

Q = 2.6

4 0

3 years ago

A thin-walled tube with a diameter of 6 mm and length of 20 m is used to carry exhaust gas from a smoke stack to the laboratory

Molodets [167]

Answer:

Explanation:

Mean temperature is given by

$T_mean = \frac{T_i + T_ \infinity}{2}\\\\T_mean = \frac{200 + 15}{2}$

Tmean = (Ti + T∞)/2

$T_mean = 107.5^{0}$

Tmean = 107.5⁰C

Tmean = 107.5 + 273 = 380.5K

Properties of air at mean temperature

v = 24.2689 × 10⁻⁶m²/s

α = 35.024 × 10⁻⁶m²/s

$\mu$ = 221.6 × 10⁻⁷N.s/m²

$\kappa$ = 0.0323 W/m.K

Cp = 1012 J/kg.K

Pr = v/α = 24.2689 × 10⁻⁶/35.024 × 10⁻⁶

= 0.693

Reynold's number, Re

Pv = 4m/πD²

where Re = (Pv * D)/ $\mu$

Substituting for Pv

Re = 4m/(πD $\mu$ )

= (4 x 0.003)/( π × 6 ×10⁻³ × 221.6 × 10⁻⁷)

= 28728.3

Since Re > 2000, the flow is turbulent

For turbulent flows, Use

Dittus - Doeltr correlation with n = 0.03

Nu = 0.023Re⁰⁸Pr⁰³ = (h₁D)/k

(h₁ × 0.006)/0.0323 = 0.023(28728.3)⁰⁸(0.693)⁰³

(h₁ × 0.006)/0.0323 = 75.962

h₁ = (75.962 × 0.0323)/0.006

h₁ = 408.93 W/m².K

4 0

3 years ago