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Allushta [10]
3 years ago
12

The ultraviolet region of the electromagnetic spectrum extends beyond violet in the visible region. Knowing the relationship bet

ween wavelength and frequency, predict how the frequency of ultraviolet radiation compares to that of visible light. Explain how you came to your conclusion.
Physics
1 answer:
madreJ [45]3 years ago
7 0
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Hook's law describes an ideal spring. Many real springs are better described by the restoring force (FSp)s=−kΔs−q(Δs)^3, where q
kvasek [131]

Answer

given,

k = 250 N/m

q = 900 N/m³

(FSp)s=−kΔs−q(Δs)^3

work done = Force x displacement

W = \int {F. dx}

limits are x = 0 to x = 0.15 m

work done

W = \int_0^{0.15} (k x + q x^3)\ dx

W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15

W = \dfrac{300\times 0.15^2}{2}+\dfrac{900\times 0.15^4}{4}

W = 3.375 + 0.1139

W = 3.3488 J

b) % cubic term =\dfrac{0.1139}{3.3488}

   % cubic term =3.4\ %

7 0
3 years ago
DNA molecules store genetic information and allow for self-replicating life. Molecules of DNA can be long and very complex. They
Anika [276]
The answer would be C., Organic Molecule.
5 0
3 years ago
Read 2 more answers
A skier skies down a slope with an average speed of 50 km/s. How far does the skier travel in 5 minutes?
aliya0001 [1]

Answer:

15000000 m

Explanation:

From the question,

Speed (S) = Distance(d)/Time(t)

S = d/t....................... Equation 1

Make d the subject of the equation

d = St..................... Equation 2

Given: S = 50 km/s = 50000 m/s, t = 5 minutes = 5*60 seconds = 300 seconds

Substitute these values into equation 2

d = 50000(300)

d = 15000000 m

Hence the skier travels 15000000 m

6 0
3 years ago
A theory is
densk [106]
The answer is A

Theory- a hypothesis or an educated guess that has yet to be proven by experiment<span />
7 0
3 years ago
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A mass attached to a spring oscillates with a period of 22 sec. After 22 kg are​ added, the period becomes 33 sec. Assuming that
polet [3.4K]

Answer:

Mass of 17.854 kg is only attached to the spring    

Explanation:

We have given time period in first case is 22 sec

Let initially mass is m

After 22 kg are added the period becomes 33 sec

Time period of spring mass system is

T=2\pi \sqrt{\frac{m}{k}}, here m is mass and k is spring constant

From the relation we can see that

\frac{T_1}{T_2}=\sqrt{\frac{m}{m+22}}

\frac{22}{33}=\sqrt{\frac{m}{m+22}}

Squaring both side

0.444={\frac{m}{m+22}}

0.444m+9.777=m

m = 17.584 kg

So mass of 17.854 kg is only attached to the spring

7 0
3 years ago
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