Answer:
1.4m/s
Explanation:
Average velocity is the total distance covered divided by the total time taken.
Average velocity =
Total time taken = 5s + 6s = 11s
The first distance covered = velocity x time = 1.4 x 5 = 7m
second distance covered = velocity x time = 1.4 x 6 = 8.4m
So;
Average velocity =
= 1.4m/s
Answer:
a) 1.22 s
b) 9.089 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²

Time taken by the ball to reach the highest point is 1.22 seconds

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m
Answer:
When the ejected air is moving in the downward direction then the thrust force acts in the upward direction, due to reversal thrust, the jets can take off vertically without needing a runway this way.
Explanation:
Newton’s third law motion states that for every action there will be an equal and opposite reaction.
Thrust reversal is also known as reverse thrust. It acts opposite to the motion of the aircraft by providing the deceleration.
Commercial aircraft moves the ejected air in the forward direction means that the thrust will acts opposite to the motion of the aircraft that is backward direction due to thrust reversal. This thrust force might be used to decelerate the craft.
Uses of thrust reversal in practice:
When the ejected air is moving forward direction then the thrust force moving backward direction due to reversal thrust the speed of the craft slows down.
When the ejected air is moving in the downward direction then the thrust force acts in the upward direction, due to reversal thrust, the jets can take off vertically without needing a runway this way.
Answer:
The value of mass 1, m1= 6/5m
The value of mass 2, m2= 3/5m
Explanation:
case 1:
here tension and the acceleration will be:
for m1;
- mg-T=ma
- 2mg - 2T = 2ma .....1.
for m2:
adding the both equations,
2mg - 2T + 2T-mg = 2ma + ma/2
a = 2/5 g
putting the value of a into the equation 1.
mg - T = m* (2/5)g
T = 3/5 ( mg )
now
case 2:
The two identical blocks are released from the rest, the tension remains the same as the case 1.
so,
for m1:
for m2:
adding both equations we get,
2T-m2g + 2m2g - 2T = 0
m2 = m1 / 2
T = m1*g / 2
here we know that
T (case1) = T (case2)
3/5 ( mg ) = m1*g / 2
m1 = 6/5 m
hence
m2 = 3/5 m
learn more about tension here:
<u>brainly.com/question/23590078</u>
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