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arlik [135]
3 years ago
9

How do I solve for x in a parallelogram?

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
Which parallelogram so I can find ×
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Which number is not a factor of 12 and a multiple of 6
Salsk061 [2.6K]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
1. tentukan hasil dari 243⅔?
Vesnalui [34]

Penjelasan langkah demi langkah:

1)

= 243^{\frac{2}{3} }\\= (\sqrt[3]{243})^2\\= 7^2\\= 49

2) √32 +3√18-2√50

= √16*2 +3√9*2-2√25*2

= 4√2 + 3(3√2)-2(5√2)

= 4√2 + 9√2-10√2

= 13√2-10√2

= 3√2

3) 1000 ⅔×64⅙

 = (\sqrt[3]{1000}) ^2 \times (2^6)^{1/6}  \\= 10^2 \times 2\\= 100 \times 2\\= 200

4) 3/4+√2

3/4+\sqrt{2} \\= \frac{3+4\sqrt{2} }{4 }

5) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

6) 12/3+√3

= 4+√3

7) √1000—2√40

= 10 -2 (√4*10)

= 10-2(2√10)

= 10 - 4√10

8) 2- ¹+3-¹

= \frac{1}{2} + \frac{1}{3}\\ = \frac{3+2}{6}\\ = \frac{5}{6}

9)

\frac{5}{\sqrt{5} }\\ merasionalisasikan\\= \frac{5}{\sqrt{5} }\times \frac{\sqrt{5} }{\sqrt{5} }\\= \frac{5\sqrt{5} }{\sqrt{25} }\\= \frac{5\sqrt{5} }{5}\\ = \frac{\sqrt{5} }{1}

Jika pernyataannya opsional, penyebutnya adalah 1

10) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

7 0
3 years ago
If (-1, y) lies on the graph of y=2^2x then y=
zubka84 [21]

Answer:

y is 1/4 when x is -1 if I did interpret your equation right. Please see that I did.

I believe the equation to be y=2^{2x}.  If you meant y=2^2x, please let me know.

Thanks kindly.

Step-by-step explanation:

If (-1,y) lies on the graph of y=2^{2x}, then by substitution we have:

y=2^{2\cdot -1}.  

We just need to simplify to determine y:

y=2^{2 \cdot -1}  

Multiply the 2 and -1:

y=2^{-2}

Use reciprocal rule for exponents to get rid of the negative:

y=\frac{1}{2^2}

2^2 just means 2(2):

y=\frac{1}{2(2)}

y=\frac{1}{4}.

8 0
3 years ago
This is for a mastery
valkas [14]

Answer:b

Step-by-step explanation:

3 0
3 years ago
I am having trouble with converges and diverges<br>​
inna [77]

Answer:

d. converges, -25

Step-by-step explanation:

An infinite geometric series converges if the absolute value of the common ratio is less than 1.

Here, the common ratio is 4/5:

| 4/5 | = 4/5 < 1

So the series converges.  The sum of an infinite geometric series is:

S = a₁ / (1 − r)

where a₁ is the first term and r is the common ratio.

Here, a₁ = -5 and r = 4/5:

S = -5 / (1 − 4/5)

S = -25

5 0
3 years ago
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