Answer:
b. about 63.9 units and 41.0 units
Step-by-step explanation:
In question ∠a= 29° and Side of a= 15 and b= 20
Using sine rule of congruence of triangle.
⇒ ![\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bsin%20A%7D%20%3D%20%5Cfrac%7Bb%7D%7Bsin%20B%7D%20%3D%20%5Cfrac%7Bc%7D%7Bsin%20C%7D)
⇒ ![\frac{15}{Sin 29} = \frac{20}{sin B}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7BSin%2029%7D%20%3D%20%5Cfrac%7B20%7D%7Bsin%20B%7D)
Using value of sin 29°
⇒ ![\frac{15}{0.49} = \frac{20}{sin B}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B0.49%7D%20%3D%20%5Cfrac%7B20%7D%7Bsin%20B%7D)
Cross multiplying both side.
⇒ Sin B= ![\frac{20\times 0.49}{15} = 0.65](https://tex.z-dn.net/?f=%5Cfrac%7B20%5Ctimes%200.49%7D%7B15%7D%20%3D%200.65)
∴ B= 41°
Now, we have the degree for ∠B= 41°.
Next, lets find the ∠C
∵ we know the sum total of angle of triangle is 180°
∴∠A+∠B+∠C= 180°
⇒ ![29+41+B= 180](https://tex.z-dn.net/?f=29%2B41%2BB%3D%20180)
subtracting both side by 70°
∴∠C= 110°
Now, again using the sine rule to find the side of c.
![\frac{b}{SinB} = \frac{c}{SinC}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%7D%7BSinB%7D%20%3D%20%5Cfrac%7Bc%7D%7BSinC%7D)
⇒![\frac{20}{sin41} = \frac{C}{sin110}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7Bsin41%7D%20%3D%20%5Cfrac%7BC%7D%7Bsin110%7D)
Using the value of sine and cross multiplying both side.
⇒ C= ![\frac{20\times 0.94}{0.65} = 28.92](https://tex.z-dn.net/?f=%5Cfrac%7B20%5Ctimes%200.94%7D%7B0.65%7D%20%3D%2028.92)
∴ Side C= 28.92.
Now, finding perimeter of angle of triangle
Perimeter of triangle= a+b+c
Perimeter of triangle= ![(15+20+28.92)= 63.9](https://tex.z-dn.net/?f=%2815%2B20%2B28.92%29%3D%2063.9)
∴ Perimeter of triangle= 63.9 units
The expression equivalent to 1/36 are :-
![\frac{1}{36} \: = \: \frac{2}{72} ; \frac{3}{108} ; \frac{4}{144} ; \frac{5}{180}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B36%7D%20%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cfrac%7B2%7D%7B72%7D%20%3B%20%5Cfrac%7B3%7D%7B108%7D%20%3B%20%5Cfrac%7B4%7D%7B144%7D%20%3B%20%5Cfrac%7B5%7D%7B180%7D%20)
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Answer:
Step-by-step explanation:
Area of the rectangular piece A = xy
x is the length
y is the width
Perimeter =2x+2y
Given
Perimeter = 3044yds
3044 = 2x+2y
1522 = x+y
x = 1522-y
Substitute into the formula for area
A = xy
A = (1522-y)y
A = 1522y-y²
To maximize the area, dA/dy must be zero
dA/dy = 1522-2y
0 = 1522-2y
2y = 1522
y = 1522/2
y = 761
Since x+y = 1522
X+761 = 1522
X = 761
Dimension is 761yd by 761yd
Area = 761×761 = 579121yd²
a). (17º-17'-17") = 17<span><span>º + 17'/60 + 17"/3600 = </span>17.288055...</span><span>º
</span>17.288055...º / 4 = 4.322...º = <em>4</em><span><em>º - 19' - 19.25" </em><em /></span><span><== <span>a resposta</span>
b) (18º: 8 + 23º: 4 - 8º)
18</span><span>º / 8 = 2.25</span><span>º
23</span><span><span>º / 4 = </span> 5.75</span><span>º
(2.25</span><span>º + 5.75</span><span><span>º </span>- 8º) = <em>0</em></span> <== a resposta
Answers:
Step-by-step explanation:
Our equation is:
With f meaning "fare" (price) and m meaning "miles".
Question 7 - Juan's fare for his ride costs $6.05. We must solve for
.
Step 1. Substitute - <em>Substitute the fare for
in the equation.</em>
![6.05=2.25+0.20(m-1)](https://tex.z-dn.net/?f=6.05%3D2.25%2B0.20%28m-1%29)
Step 2. Simplify/Solve - Solve for
.
![6.05=2.25+0.20(m-1)](https://tex.z-dn.net/?f=6.05%3D2.25%2B0.20%28m-1%29)
<em>- Distribute</em>
![6.05=2.25+0.2m-0.2](https://tex.z-dn.net/?f=6.05%3D2.25%2B0.2m-0.2)
<em>- Subtract 0.2 from 2.25</em>
![6.05=2.05+0.2m](https://tex.z-dn.net/?f=6.05%3D2.05%2B0.2m)
<em>- Subtract -2.05 from 6.05</em>
![4=0.2m](https://tex.z-dn.net/?f=4%3D0.2m)
<em>- Divide both sides by 0.2</em>
![20=m](https://tex.z-dn.net/?f=20%3Dm)
<u>And you have your answer of 20 miles.</u>
Question 8 - Same equation, different fare.
Step 1. Substitute
![7.65=2.25+0.20(m-1)](https://tex.z-dn.net/?f=7.65%3D2.25%2B0.20%28m-1%29)
Step 2. Solve
![7.65=2.25+0.20(m-1)\\7.65=2.25+0.20m-0.20\\7.65=2.05+0.20m\\5.6=0.20m\\28=m](https://tex.z-dn.net/?f=7.65%3D2.25%2B0.20%28m-1%29%5C%5C7.65%3D2.25%2B0.20m-0.20%5C%5C7.65%3D2.05%2B0.20m%5C%5C5.6%3D0.20m%5C%5C28%3Dm)
And like so, we have ![m = 28](https://tex.z-dn.net/?f=m%20%3D%2028)
<em>The equation given is
. S = typing speed, w = words per 5 mins, and e= errors.</em>
Question 9 -
<em>We are given this information: S = 55, W = 285. We are solving for e</em>.
Substitute -
![55=\frac{1}{5} (285 -10e)](https://tex.z-dn.net/?f=55%3D%5Cfrac%7B1%7D%7B5%7D%20%28285%20-10e%29)
Solve -
![55=\frac{1}{5} (285 -10e)\\55=\frac{1}{5} (285 -10e)\\55= 57-2e\\-2=-2e\\1=e](https://tex.z-dn.net/?f=55%3D%5Cfrac%7B1%7D%7B5%7D%20%28285%20-10e%29%5C%5C55%3D%5Cfrac%7B1%7D%7B5%7D%20%28285%20-10e%29%5C%5C55%3D%2057-2e%5C%5C-2%3D-2e%5C%5C1%3De)
So they would make 1 error.
Question 10 -
<em>Information given: 300 = w, 5=e. We are solving for S</em>
Substitute -
![S= \frac{1}{5} (300-10(5))](https://tex.z-dn.net/?f=S%3D%20%5Cfrac%7B1%7D%7B5%7D%20%28300-10%285%29%29)
Solve -
![S= \frac{1}{5} (300-10(5))\\S= \frac{1}{5} (300-50)\\S= \frac{1}{5} (300-50)\\S= \frac{1}{5} (250)\\S= 50](https://tex.z-dn.net/?f=S%3D%20%5Cfrac%7B1%7D%7B5%7D%20%28300-10%285%29%29%5C%5CS%3D%20%5Cfrac%7B1%7D%7B5%7D%20%28300-50%29%5C%5CS%3D%20%5Cfrac%7B1%7D%7B5%7D%20%28300-50%29%5C%5CS%3D%20%5Cfrac%7B1%7D%7B5%7D%20%28250%29%5C%5CS%3D%2050)
Their speed is 50.
Question 11 -
<em>Information given: S = 65, e = 4. We are solving for w.</em>
Substitute -
![65=\frac{1}{5} (w-10(4))](https://tex.z-dn.net/?f=65%3D%5Cfrac%7B1%7D%7B5%7D%20%28w-10%284%29%29)
Solve -
![65=\frac{1}{5} (w-10(4))\\65=\frac{1}{5} (w-40)\\65=\frac{1}{5}w-8\\73=\frac{1}{5}w\\365=w](https://tex.z-dn.net/?f=65%3D%5Cfrac%7B1%7D%7B5%7D%20%28w-10%284%29%29%5C%5C65%3D%5Cfrac%7B1%7D%7B5%7D%20%28w-40%29%5C%5C65%3D%5Cfrac%7B1%7D%7B5%7Dw-8%5C%5C73%3D%5Cfrac%7B1%7D%7B5%7Dw%5C%5C365%3Dw)
So w = 365.