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3 years ago

How far will u go if your wheel' diameter 34in?

Physics

1 answer:

Lapatulllka [165]3 years ago

4 0

Technically you can go forever on and on, but maybe your question was like how many rotations in a certain distance?

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Define Nuclear Physics ?

murzikaleks [220]

Answer:

Definition. Nuclear physics is the study of the protons and neutrons at the centre of an atom and the interactions that hold them together in a space just a few femtometres (10-15 metres) across. Example nuclear reactions include radioactive decay, fission, the break-up of a nucleus, and fusion, the merging of nuclei.

Explanation:

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3 0

3 years ago

Read 2 more answers

The barometric pressure at sea level is 30 in of mercury when that on a mountain top is 29 in. If the specific weight of air is

stealth61 [152]

To solve this problem we will apply the concepts related to pressure, depending on the product between the density of the fluid, the gravity and the depth / height at which it is located.

For mercury, density, gravity and height are defined as

$\rho_m = 846lb/ft^3$

$g = 32.17405ft/s^2$

$h_1 = 1in = \frac{1}{12} ft$

For the air the defined properties would be

$\rho_a = 0.0075lb/ft^3$

$g = 32.17405ft/s^2$

$h_2 = ?$

We have for equilibrium that

$\text{Pressure change in Air}=\text{Pressure change in Mercury}$

$\rho_m g h_1 = \rho_a g h_2$

Replacing,

$(846)(32.17405)(\frac{1}{12}) = (0.0075)(32.17405)(h_2)$

Rearranging to find $h_2$

$h_2 = \frac{(846)(32.17405)(\frac{1}{12}) }{(0.0075)(32.17405)}$

$h = 9400ft$

Therefore the elevation of the mountain top is 9400ft

7 0

3 years ago

What type on msd causes inflammation of the tendons that correct bones to muscles

svp [43]

I believe it would be Tendonitis

8 0

3 years ago

Does this diagram illustrate the second law of thermodynamics? Why or why not

Savatey [412]

<h2>Answer:</h2>

The diagram is not showing the second law of thermodynamics. It is the demonstration of 1st law of thermodynamics.

<h3>Explanation:</h3>

Second law of thermodynamics describes the entropy of the system increase with time, it does not decrease with time. It is constant for ideal systems.

While in first law of thermodynamics, it is stated that the energy of a system can not be lost but it is transferred from one form to other form.

And in this picture, it is shown that the energy released from heat source to cold sink is used in doing work.

Work and heat are forms of energy.

5 0

4 years ago

Read 2 more answers

I've got an energy and work problem. The premise of the problem is:

Alenkasestr [34]

Refer to the diagram shown below.

μ = the coefficient of dynamic friction between the crate and the ramp.

1. The applied force of F acts over a distance, d.
The work done is F*d.

2. The component of the weight of the crate acting down the ramp is
mg sin(30) = 0.5mg.
The work done by this force is 0.5mgd.

3. The normal force is N = mgcos(30) = 0.866mg.
This force is perpendicular to the ramp, therefore the work done is zero.

4. The frictional force is μN = μmgcos(30) = 0.866μmg.
The work done by the frictional force is 0.866μmgd.

5. The total force acting on the crate up the ramp is
F - mgsin(30) - μmgcos(30) = F - mg(0.5 - 0.866μ)

6. The work done on the crate by the total force is
d*(F - 0.5mg - 0.866μmg)

7 0

4 years ago