Answer:
Explanation:
Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as
W = F×d
or
W = 
.................................. Equation 1
Where b = upper limit, a = lower limit, Fx = expression of force.
<em>Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²</em>
Substituting these values into equation 1
<em>W = 
</em>
W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ
Work = upper limit - lower limit
Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2
Substituting the values of a and b into equation 2
Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]
Work = [5.2 + 26.53 -3.29 + C] - C
Work = 28.44 J
Work done by the force = 28.44 J.
In order to calculate the time taken by the snowball to reach the highest point in its journey, we need to consider the variables along the y-direction.
Let us list out what we know from the question so that we can decide on the equation to be used.
We know that Initial Y Velocity
= 8.4 m/s
Acceleration in the Y direction 
= -9.8 m/
, since the acceleration due to gravity points in the downward direction.
Final Y Velocity 
= 0 because at the highest point in its path, an object comes to rest momentarily before falling down.
Time taken t = ?
From the list above, it is easy to see that the equation that best suits our purpose here is 
Plugging in the numbers, we get 0 = 8.4 - (9.8)t
Solving for t, we get t = 0.857 s
Therefore, the snowball takes 0.86 seconds to reach its highest point.
Probably 90 j but im not sure I haven’t done any work like this in a while
C volume because the volume take up the Mater and space around it thing
Answer:
20.96 h
Explanation:
The perimeter of the track is 2*pi*r = 20pi miles
In 10 hours, car B would have moved 20miles. So, when Car A leaves from point X, car B is 20pi - 20 miles from point X counter-clockwise and car A.
From here, we can express the distance of A from X like this:
xa = 3t
And the distance of B would be:
xb = 20pi - 20 - 2t
The time t where they would passed each other and put 12 miles between them would be the one where xa - xb is equal to 12:
xa - xb = 12
3t - (20pi - 20 - 2t) = 12
5t = 20 pi - 8
t = (20pi - 8)/5 = 10.96 h
Remember to add this value to the 10 hours car B had already been racing:
t = 20.96h
