What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Answer:
3.96
Step-by-step explanation:
Aminah increased the price of the book to
. James increased the price of the book to
. So James needs to give
to Khalid.
Answer: $0.32
Step-by-step explanation:
128 / 8 = 16
1 / 16 = 0.0625
0.0625 * 5.12 = 0.32
Simpler Answer:
128 / 8 = 16
5.12 / 16 = 0.32
Answer:
There is a 13.40% probability that a message is spam, given that it contains the word "text" (or "txt").
Step-by-step explanation:
The problem states that
There are 5574 messages.
There are 747 messages that are spam.
Every message contains the word text.
Bayes rule:
What is the probability of B, given that A?
![P(A/B) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28A%2FB%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In this problem, we have that
A is containing the word text. So ![P(A) = 1](https://tex.z-dn.net/?f=P%28A%29%20%3D%201)
So
![P(A/B) = \frac{P(A \cap B)}{P(A)} = P(A \cap B)](https://tex.z-dn.net/?f=P%28A%2FB%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D%20%3D%20P%28A%20%5Ccap%20B%29)
is containing the word text and being a spam message. So:
![P(A \cap B) = \frac{747}{5574} = 0.1340](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%20%5Cfrac%7B747%7D%7B5574%7D%20%3D%200.1340)
There is a 13.40% probability that a message is spam, given that it contains the word "text" (or "txt").
Answer:
the area left to 51 on normal distribution curve
Step-by-step explanation:
we have to find the probability that at most 51 it means the probability of less than 51 . The probability of at most 51 or less than 51 on the normal distribution curve will be the area lest side of 51 for example if we have to find the are of at least 51 then the area on the normal distribution curve will be right of 51
so the answer will be the area left side of 51