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Artemon [7]
3 years ago
8

How many atoms of K are present in 195.49 grams of K? 3.0110 × 1024 6.0220 × 1024 1.1772 × 1026 4.5797 × 1027

Chemistry
1 answer:
Ierofanga [76]3 years ago
3 0
<h2>Hello!</h2>

The answer is: 3.0110x10^{24}

<h2>Why?</h2>

First, we need to look for the K molecular mass:

K=39,098 g/mol

Also, we need to remember that 1 mol of a compound or element is equal to 6,022x10^{23} of that compound.

From the statement, we are asked to calculate how many atoms of K are present in 195,49 of K.

So, doing the calculations, we have:

195,49g*\frac{1mol}{39,08}*\frac{6,022x10^{23} atoms}{1 mol K} =3,0110x10^{24} \\

So, we have 3.0110x10^{24} atoms of K in 195,49 grams of K.

Have a nice day!

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