Question

How many atoms of K are present in 195.49 grams of K? 3.0110 × 1024 6.0220 × 1024 1.1772 × 1026 4.5797 × 1027

Answer 1

Hello!

The answer is: $3.0110x10^{24}$

Why?

First, we need to look for the K molecular mass:

$K=39,098 g/mol$

Also, we need to remember that 1 mol of a compound or element is equal to $6,022x10^{23}$ of that compound.

From the statement, we are asked to calculate how many atoms of K are present in 195,49 of K.

So, doing the calculations, we have:

$195,49g*\frac{1mol}{39,08}*\frac{6,022x10^{23} atoms}{1 mol K} =3,0110x10^{24}$

So, we have $3.0110x10^{24}$ atoms of K in 195,49 grams of K.

Have a nice day!