Which famous scientist is credited as the founder of the scientific method?

A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from x = −

romanna [79]

Answer:

The speed of electron is $1.5\times10^{7}\ m/s$

Explanation:

Given that,

Electric field $E=1.50\times10^{3}\ N/C$

Distance = -0.0200

The electron's speed has fallen by half when it reaches x = 0.190 m.

Potential energy $P.E=5.04\times10^{-17}\ J$

Change in potential energy $\Delta P.E=-9.60\times10^{-17}\ J$ as it goes x = 0.190 m to x = -0.210 m

We need to calculate the work done by the electric field

Using formula of work done

$W=-eE\Delta x$

Put the value into the formula

$W=-1.6\times10^{-19}\times1.50\times10^{3}\times(0.190-(-0.0200))$

$W=-5.04\times10^{-17}\ J$

We need to calculate the initial velocity

Using change in kinetic energy,

$\Delta K.E = \dfrac{1}{2}m(\dfrac{v}{2})^2+\dfrac{1}{2}mv^2$

$\Delta K.E=\dfrac{-3mv^2}{8}$

Now, using work energy theorem

$\Delta K.E=W$

$\Delta K.E=\Delta U$

So, $\Delta U=W$

Put the value in the equation

$\dfrac{-3mv^2}{8}=-5.04\times10^{-17}$

$v^2=\dfrac{8\times(5.04\times10^{-17})}{3m}$

Put the value of m

$v=\sqrt{\dfrac{8\times(5.04\times10^{-17})}{3\times9.1\times10^{-31}}}$

$v=1.21\times10^{7}\ m/s$

We need to calculate the change in potential energy

Using given potential energy

$\Delta U=-9.60\times10^{-17}-(-5.04\times10^{-17})$

$\Delta U=-4.56\times10^{-17}\ J$

We need to calculate the speed of electron

Using change in energy

$\Delta U=-W=-\Delta K.E$

$\Delta K.E=\Delta U$

$\dfrac{1}{2}m(v_{f}^2-v_{i}^2)=4.56\times10^{-17}$

Put the value into the formula

$v_{f}=\sqrt{\dfrac{2\times4.56\times10^{-17}}{9.1\times10^{-31}}+(1.21\times10^{7})^2}$

$v_{f}=1.5\times10^{7}\ m/s$

Hence, The speed of electron is $1.5\times10^{7}\ m/s$

4 0

3 years ago

Two planets with the same mass and atmospheric conditions orbit a single star. Planet A is closer to the star than Planet B. Whi

8_murik_8 [283]

Answer:

is not this one Planet B is expected to be hotter than Planet A.

Explanation:

3 0

2 years ago

Solve the equation of motion, using Newton's 1 Law F 0, for a general case of M the mass of the wooden block and u, being the co

vodka [1.7K]

Answer:

Explanation:

The first thing to have to make a diagram where we indicate the forces acting on the block, see attached. We have the following

The weight (W) that is vertical

The friction force (fr) that opposes the movement

The driving force (F)

The normal (N) which is the reaction to the support of the body and is perpendicular to the surface

We write a reference system where one axis is parallel to the surface (x axis) and the other is perpendicular to it (Y axis) we decompose the forces on these axes, we see that the only force we have to decompose r is the weight

sin θ = Wx / W ⇒ Wx = W sin θ

cos θ = Xy / W ⇒ Wy = Wcos θ

We write Newton's equations for each axis

N- Wy = 0

F -fr -Wx = m a (1)

The expression for the friction force is

fr = μ N

N = Wy

N = W cos θ

fr = μ mg cosT

We hope, we simplify the acceleration of equation 1

a = F - μ mg cos θ -mg sinθ

a = F - mg (μ cos θ -sin θ)

This is the general equation for movement.

3 0

3 years ago

Precautions taken when doing experiment on simple pendulum

olchik [2.2K]

Answer:

1.)The bob of pendulum should be displaced with a small angle.

2) The amplitude of the oscillation of a simple pendulum should be small.

3) Fans should be switched off to reduce the air resistance.

4)The simple pendulum should be oscillate in a vertical plane

Hope this helped you

7 0

4 years ago

The radius of The moon is one_fourth and its mass is one eighty-first that of The earth. If The acceleration due to gravity on T

77julia77 [94]

$g_{moon} = g_{earth}* \frac{( \frac{1}{81} )}{ (\frac{1}{ 4^{2}})} = g_{earth} * \frac{16}{81} = 9.8*16/81= 1.935$

7 0

3 years ago