Ask question

Ask question

All categories

3 years ago

12

Contact force that acts to resist sliding between two touching surfaces

1 answer:

Black_prince [1.1K]3 years ago

3 0

I think that the answer is friction

You might be interested in

What is the name of the process the puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP?

hoa [83]

I think the correct answer is hydrolysis. The name <span>of the process that puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP is called hydrolysis. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>

6 0

3 years ago

Is nuclear fission hybrid physics or geothermal phsics

Semenov [28]

Nuclear fission is geothermal physics.

6 0

3 years ago

Read 2 more answers

Express 79 m in units of (a) centimeters

dem82 [27]

Answer: a) 7,00 centimeters

(b) 259. 19 feet

(c) 3110.28 inches

(d) 0.049 miles

Explanation:

(a) We know that 1 meter = 100 centimeters

Therefore,

$79\ m= 7,900\text{ centimeters}$

(b)Since 1 meter = 3.28084 feet

Then, $79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}$

(c) Since, 1 feet = 12 inches.

$79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}$

(d) $\text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}$

$79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}$

8 0

3 years ago

Can someone please answer my question please. thank you ❤️

faust18 [17]

<h3>₳ ₦ ₷ ￦ € r : </h3>

BATANGAS

560 km

PUERTO PRINCESSA

400 km

DAVAO

480 km

(´｡• ω •｡`) ♡

6 0

2 years ago

The charges Q1=Q and Q2=4Q that are a distance d apart, repel each other with a force of 1.60 N. What would be the force between

gladu [14]

Answer:

50.4 N

Explanation:

Q1 = Q

Q2 = 4 Q

Distance = d

The force is given by

$F = \frac{KQ_{1}Q_{2}}{d^{2}}$

$1.60 = \frac{4KQ^{2}}{d^{2}}$ .... (1)

Now,

Q3 = 2 Q

Q4 = 7 Q

distance = d/3

$F' = \frac{9KQ_{3}Q_{4}}{d^{2}}$

$F' = \frac{126KQ^{2}}{d^{2}}$ .... (2)

Divide equation (2) by equation (1), we get

F' / 1.60 = 126 / 4

F' = 50.4 N

Thus, the force is 50.4 N.

7 0

3 years ago