Which choice is the correct answer?
1 answer:
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Answer:
The correct option is;
a. 12 pie cm
Step-by-step explanation:
Cavalieri's principle states that if the cross-sectional area of two or more figures of the same altitude are the same at each level of the figures, then the volumes of the figures are also the same;
Given that the base area of the square based prism and the cylinder are the same, and that the square based prism and the cylinder have equal height of 4 cm, then by Cavalieri's principle, their volumes are the same
The volume of the square based prism = 452 cm³
Therefore, the volume of the cylinder (of equal base area) = 452 cm³
The formula for the volume of square based prism = Area of base × Height
∴ The volume of square based prism, 452 cm³ = Area of base × 4 cm
Which gives;
Area of the base of the square based prism = 452/4 = 113 cm²
The area of the base of the cylinder = The area of the base of the square based prism = 113 cm²
The area of the base of the cylinder, is given by the following equation;
= π×r² = 113 cm²
r = √(113/π) = √35.97 ≈ √36 = 6 cm
The circumference of the base of the cylinder, is given by the following equation
= 2×π×r ≈ 2×π×6 = 12×π cm
The correct option is 12 pie cm.
The student's friend watch 1.5 movies every week.
Data provided to us {2, 14, 1, 2, 0, 1, 0, 2}.
Number of data values = 8
Sorted or rearranged data {0, 0, 1, 1, 2, 2, 2, 14}
Median of the data provided;
Median is the mid point value of the data provided to us, but as in this case there are 8 data provided (even number of data), we will take the average of the 2 mid values of the data.
Mid Values = 1 and 2
Mean of the data provided;
As we know, The data values provided are 0, 1 and 2, and there is 14 as well in the data which is the maximum value in the data provided to us but the value is far from the other data values provided to us. Therefore, the data value 14 is considered to be an outlier.
An outlier is the maximum value that increases the mean, which makes it larger than it should be.
If we were to compute the mean without the outlier,
Now, we have understood that the mean is sensitive to outlier can be easily manipulated. thus, mean is not the right option to go for in this case.
Therefore, the median value of 1.5 is the right option.
Hence, the student's friend watch 1.5 movies every week.
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