Question

A 24% acid solution is mixed with a 14% acid solution to form a 19% acid solution. How many liters of the 24% acid solution are used to make 10 liters of the 19% acid solution?

Answer 1

Answer: 5 Liters

Explanation:

According to the dilution law,

$M_1V_1+M_2V_2=M_3V_3$

where,

$M_1$ = concentration of first solution = 24%

$V_1$ = volume of first solution = x L

$M_2$ = concentration of second solution = 14%

$V_2$ = volume of second solution = (10-x) L

$M_3$ = concentration of final solution = 19%

$V_2$ = volume of final solution = 10 L

Putting i the values, we get:

$24\times x+14\times (10-x)=19\times 10$

$x=5L$

Therefore, 5 Liters of the 24% acid solution are used to make 10 liters of the 19% acid solution.