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3 years ago

Which shows the formula for converting from degrees Celsius to degrees Fahrenheit?

Physics

2 answers:

masha68 [24]3 years ago

8 0

Explanation:

The two scales for measuring the temperature of an object are Celsius scale and Fahrenheit scale. Mathematically, it can be written as :

$^{\circ} F=(\dfrac{9}{5}\times ^{\circ}C)+32$

Where

°F = degree Fahrenheit

°C = degree Celsius

For example, if T = 30°C. It can be converted to °F as :

$^{\circ} F=(\dfrac{9}{5}\times 30)+32$

$^{\circ} F=86$

So, 30°C is equal to 86 Fahrenheit. Hence, this is the required solution.

Alina [70]3 years ago

3 0

This is a question that makes us REALLY want to know what "Which" means.

If you included a list of answer choices with your question, then the correct formula isn't on it.

The formula for converting temperature from degrees Celsius to degrees Fahrenheit is:

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A laser beam of wavelength 439.4 nm is inci- dent on two slits 0.306 mm apart.

Ivahew [28]

Constructive interference happens when this condition is satisfied:
$dsin(\theta)=m\lambda; m=1,2,3,4,5,...$
This means that the difference in the distance traveled by the waves, from the slit to the screen, is equal to the whole multiple of the wavelength.
If we say that the distance between two interference fringes is much smaller than the distance from the slit to the screen, we can use the following approximation:
$sin(\theta)=\frac{y}{L}$
Finally for the bright spots we have:
$y=\frac{m\lambda L}{d}$
The spacing between bright spots is:
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3 years ago

The mass of a hot-air balloon and its occupants is 381 kg (excluding the hot air inside the balloon). The air outside the balloo

Kamila [148]

Answer:

In order to lift off the ground, the air in the balloon must be heated to 710.26 K

Explanation:

Given the data in the question;

P = 1.01 × 10⁵ Pa

V = 480 m³

ρ = 1.29 kg/m³

M = 381 kg

we know that; R = 8.31 J/mol.K and the molecular mass of air μ = 29 × 10⁻³ kg/mol

let F represent the force acting upward.

Now in a condition where the hot air balloon is just about to take off;

F - Mg - m $_g$ g = 0

where M is the mass of the balloon and its occupants, m $_g$ is the mass of the hot gas inside the balloon.

the force acting upward F = Vρg

Vρg - Mg - m $_g$ g = 0

solve for m $_g$

m $_g$ = ( Vρg - Mg ) / g

m $_g$ = Vρg/g - Mg/g

m $_g$ = ρV - M ------- let this be equation 1

Now, from the ideal gas law, PV = nRT

we know that number of moles n = m $_g$ / μ

where μ is the molecular mass of air

PV = (m $_g$ /μ)RT

solve for T

μPV = m $_g$ RT

T = μPV / m $_g$ R -------- let this be equation 2

from equation 1 and 2

T = μPV / (ρV - M)R

so we substitute in our values;

P = 1.01 × 10⁵ Pa

V = 480 m³

ρ = 1.29 kg/m³

M = 381 kg

we know that; R = 8.31 J/mol.K and the molecular mass of air μ = 29 × 10⁻³ kg/mol

T = [ (29 × 10⁻³) × (1.01 × 10⁵) × 480 ] / [ (( 1.29 × 480 ) - 381)8.31 ]

T = 1405920 / 1979.442

T = 710.26 K

Therefore, In order to lift off the ground, the air in the balloon must be heated to 710.26 K

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Answer:

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N-W = 0

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fr = m a

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a = 6.076 m / s²

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v² = v₀² - 2 a x

suppose v = 0

v₀ = $\sqrt{2ax}$ Ra 2ax

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v₀ = $\sqrt{2 \ 6076 \ 60}$

v₀ = 27.00 m / s

let's slow down to the english system

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v₀ = 60.38 mi / h

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I don't know

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