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Tema [17]
3 years ago
9

A very long, solid cylinder with radius R has positive charge uniformly distributed throughout it, with charge per unit volume \

rhorho.
(a) Derive the expression for the electric field inside the volume at a distance r from the axis of the cylinder in terms of the charge density \rhorho.
(b) What is the electric field at a point outside the volume in terms of the charge per unit length \lambdaλ in the cylinder?
(c) Compare the answers to parts (a) and (b) for r = R.
(d) Graph the electric-field magnitude as a function of r from r = 0 to r = 3R.

Physics
1 answer:
Rashid [163]3 years ago
4 0

Answer:

the answers are provided in the attachments below

Explanation:

Gauss law state that the net electric field coming out of a closed surface is directly proportional to the charge enclosed inside the closed surface

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Answer:

d=691.71km

Explanation:

The time lag between the arrival of transverse waves and the arrival of the longitudinal waves is defined as:

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Explanation:

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the stimulated emission rate is equal to:

pst=(N*C*o(v))/V

where

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o(v)=(λ^2)/(4*π*tp*deltav)

Replacing values:

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the probability is equal to:

P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7

b) the rate of decay is equal to:

R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system

c) the number of photons is equal to:

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Replacing:

N=100/(3*3x10^10*8.3x10^-19)

N=1.33x10^9 photons

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