Answer:
P = 23400 [kg*m/s]
Explanation:
Momentum is defined as the product of force by the time of force duration. It can be determined by means of the following equation.
where:
P = momentum [kg*m/s]
F = force = 2600 [N]
t = time = 9 [s]
Now replacing:
![P=2600*9\\P=23400 [kg*m/s]](https://tex.z-dn.net/?f=P%3D2600%2A9%5C%5CP%3D23400%20%5Bkg%2Am%2Fs%5D)
Otal energy= PEmax on the spring = KEmax of the oject
<span>Total Energy= KE+PE at v or x not maximum. </span>
<span>Using the second line </span>
<span>E= 3/4 E + PE </span>
<span>PE = 1/4 E </span>
<span>PEmax =E = 1/2 kA^2 </span>
<span>PE=E/4 = (1/2)kA^2 / 4= kA^2/8
</span>
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Answer:
72.53 mi/hr
Explanation:
From the question given above, the following data were obtained:
Vertical distance i.e Height (h) = 8.26 m
Horizontal distance (s) = 42.1 m
Horizontal velocity (u) =?
Next, we shall determine the time taken for the car to get to the ground.
This can be obtained as follow:
Height (h) = 8.26 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
8.26 = ½ × 9.8 × t²
8.26 = 4.9 × t²
Divide both side by 4.9
t² = 8.26 / 4.9
Take the square root of both side by
t = √(8.26 / 4.9)
t = 1.3 s
Next, we shall determine the horizontal velocity of the car. This can be obtained as follow:
Horizontal distance (s) = 42.1 m
Time (t) = 1.3 s
Horizontal velocity (u) =?
s = ut
42.1 = u × 1.3
Divide both side by 1.3
u = 42.1 / 1.3
u = 32.38 m/s
Finally, we shall convert 32.38 m/s to miles per hour (mi/hr). This can be obtained as follow:
1 m/s = 2.24 mi/hr
Therefore,
32.38 m/s = 32.38 m/s × 2.24 mi/hr / 1 m/s
32.38 m/s = 72.53 mi/hr
Thus, the car was moving at a speed of
72.53 mi/hr.
Yes it’s is a force multiplier
