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pickupchik [31]
3 years ago
9

Which of the following are examples of negative brain plasticity? (Note: You will

Physics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

Negative neuroplasticity. Environmental factors that decrease cognitive reserve, inhibits neuronal connections and causes sparse neuronal connections. The result if that over time the brain becomes less efficient.A lot of the ways in which our brain function degrades that we typically think of as part of “just getting old” is really negative neuroplastic change. As people grow older, they unknowingly contribute to their brain's decline by not using and challenging it as much. For example, a person retires from work.Both positive neuroplasticity and negative neuroplasticity refer to the actual morphological and neurochemical changes that occur in the nervous system and brain between neurons in response to adapting to environmental demands or press (Figure 1; Vance & Crowe, 2006; Vance, Roberson, McGuiness, & Fazeli, 2010).

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A water gun fires 5 squirts per second. The speed of the squirts is 15 m/s.
stira [4]

Answer: 3.75 m

Explanation:

5 squirts in 1 second

So, 1 squirt in 1/5 second which is 0.2 second.

The difference in timing of two consecutive squirt is 0.2 second, so

time (t) = 0.2 s.

speed (s) = 15 m/s

Distance of separation (d) = ?

Now, formula for distance is

d = s × t

d = 15 × 0.2

d = 3.75 m

4 0
3 years ago
Waxing or waning moon?
Dennis_Churaev [7]

Answer:

waning gibbious

Explanation:

7 0
3 years ago
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.
Contact [7]
The center of mass is given with this formula:
x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}
Velocity is:
v=\frac{dv}{dt}
So, for the velocity of the center of mass we have:
\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\
v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\
In our case it is:
v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}
 
5 0
3 years ago
After striking both mirrors, at what angle relative to the incoming ray does the outgoing ray emerge?
PIT_PIT [208]
The appropriate response is Zero degrees. The beam will leave the two mirrors along a way parallel to the one it came in on. This is the guideline of the corner reflector, which is frequently utilized as a radar target. Take note of that the corner reflector utilizes three reflecting surfaces (that are set up at 90o from each other) rather than the two like are being utilized here. Wikipedia has a truly awesome drawing that shows this two-dimentional issue pleasantly. A moment connection is given to the article on the corner reflector and the 3-D angles.
4 0
3 years ago
A bungee cord is 30m long and when stretched a distance x itexerts a restoring force of magnitude kx. Your father-in-law (mass95
madam [21]

Answer:

The distance the bungee cord that would be stretched 0.602 m, should be selected when pulled by a force of 380 N.

Explanation:

As from the given data

the length of the rope is given as l=30 m

the stretched length is given as l'=41m

the stretched length required is give as  y=l'-l=41-30=11m

the mass is m=95 kg

the  force is  F=380 N

the gravitational acceleration is g=9.8 m/s2

The equation of  k is given by equating the energy at the equilibrium point which is given as

U_{potential}=U_{elastic}\\mgh=\dfrac{1}{2} k y^2\\k=\dfrac{2mgh}{y^2}

Here

m=95 kg, g=9.8 m/s2, h=41 m, y=11 m so

k=\dfrac{2mgh}{y^2}\\k=\dfrac{2\times 95\times 9.8\times 41}{11^2}\\k=630.92 N/m

Now the force is

F=kx\\ or

x=\dfrac{F}{k}\\

So here F=380 N, k=630.92 N/m

x=\dfrac{F}{k}\\x=\dfrac{380}{630.92}\\x=0.602 m

So the distance is 0.602 m

6 0
3 years ago
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