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2 years ago

Which of the following are examples of negative brain plasticity? (Note: You will

Physics

1 answer:

Olegator [25]2 years ago

3 0

Answer:

Negative neuroplasticity. Environmental factors that decrease cognitive reserve, inhibits neuronal connections and causes sparse neuronal connections. The result if that over time the brain becomes less efficient.A lot of the ways in which our brain function degrades that we typically think of as part of “just getting old” is really negative neuroplastic change. As people grow older, they unknowingly contribute to their brain's decline by not using and challenging it as much. For example, a person retires from work.Both positive neuroplasticity and negative neuroplasticity refer to the actual morphological and neurochemical changes that occur in the nervous system and brain between neurons in response to adapting to environmental demands or press (Figure 1; Vance & Crowe, 2006; Vance, Roberson, McGuiness, & Fazeli, 2010).

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In a simple RC circuit, at t=0 the switch is closed with the capacitor uncharged. If C=30µF, =50V and R=10k, what is the poten

sergij07 [2.7K]

Answer:

Voltage across the capacitor is 30 V and rate of energy across the capacitor is 0.06 W

Explanation:

As we know that the current in the circuit at given instant of time is

i = 2.0 mA

R = 10 k ohm

now we know by ohm's law

$V = iR$

$V = (2 mA)(10 kohm)$

$V = 20 volts$

so voltage across the capacitor + voltage across resistor = V

$V_c + 20 = 50$

$V_c = 30 V$

Now we know that

$U = \frac{q^2}{2C}$

here rate of change in energy of the capacitor is given as

$\frac{dU}{dt} = \frac{q}{C} \frac{dq}{dt}$

$\frac{dU}{dt} = (30)(2 mA)$

$\frac{dU}{dt} = 0.06 W$

3 0

2 years ago

What is the internal resistor of the cell in closed circuit?

Drupady [299]

Generally, the internal resistance of the new battery is small, about 0.2 euros, while the old battery is large, close to 1 euro ，

5 0

3 years ago

The specific heat of substance A is greater than that of substance B. Both A and B are at the same initial temperature when equa

Sonja [21]

Answer:

$m_A c_{pA} (T_{fA} -T) = m_B c_{pB} (T_{fB}- T)$

For this case, if we try to find the final temperature of A and B, we see that we will obtain an expression in terms of specific heats and masses, from the information given we know the relationship between specific heats, but we don't know the relationship that exists among the masses, then the best option for this case is:

d) More information is needed

(The relation between the masses is not given)

Explanation:

For this case we know the following info:

$c_{pA} > c_{pB}$