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zloy xaker [14]
3 years ago
5

A convex lens is placed on a flat glass plate and illuminated from above with monochromatic red light. When viewed from above, c

oncentric bands of red and dark are observed. What does one observe at the exact center of the lens where the lens and the glass plate are in direct contact
Physics
1 answer:
kipiarov [429]3 years ago
4 0

Answer:xit wou,ld becevemtjyrjtdjtdhtdjyrkuf

Explanation:

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(i) a force of 35.0 n is required to start a 6.0-kg box moving across a horizontal concrete floor, (a) what is the coefficient o
Serjik [45]

a. The force applied would be equal to the frictional force.

F = us Fn

where, F = applied force = 35 N, us = coeff of static friction, Fn = normal force = weight

 

35 N = us * (6 kg * 9.81 m/s^2)

us = 0.595

 

b. The force applied would now be the sum of the frictional force and force due to acceleration

F = uk Fn + m a

where, uk = coeff of kinetic friction

 

35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)

uk = 0.533

4 0
3 years ago
Which of the following would not be found on the electromagnetic spectrum?
kondor19780726 [428]
All wavelengths and frequencies of electromagnetic radiation ...
including visible light ... are features of the electromagnetic spectrum.

Sound waves have nothing to do with the electromagnetic spectrum.
8 0
3 years ago
he amplitude of a lightly damped harmonic oscillator decreases by 3.0% during each cycle.show answer no attempt what percentage
GrogVix [38]

The percentage of mechanical energy of the oscillator lost in each cycle is 5.91 %.

The formula for mechanical energy in an oscillator is given by

E = 1/2 kA²

It is the sum of elastic potential energy and kinetic energy.

Amplitude is nothing but the maximum displacement moved by a point on vibrating body.

It is given that the amplitude A decreases by 3%, then

(E₂ - E₁) / E₁ = [1/2 k (A₂²- A₁²)] /(1/2 k A₁²) = (A₂²- A₁²)/ A₁² = (97² - 100²)/ 100²

⇒ 5.91% of the mechanical energy is lost in each cycle.

To know more about mechanical energy:

brainly.com/question/4285515

#SPJ4

4 0
1 year ago
When is the magnitude of the acceleration of a mass on a spring at its maximum value?
DiKsa [7]

Answer:

D

Explanation:

Now we know that Force is the rate of change of momentum meaning

F= mv/t

But

mv/t = Ke

v/t = ke/m

a= ke/m

Where a is acceleration

K is constant of proportionality of tension on a spring

e is the extension substended by a string.

From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1

We would have a maximum value of acceleration.

6 0
4 years ago
An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i
Butoxors [25]

Answer:5 m/s^{2}

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Then, isolating g and taking into account sin(90\°)=1:

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

Finally:

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

7 0
3 years ago
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