Answer:
it's blurry, you need a new picture
Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Answer:
x-int: (3, 0)
y-int: (0, -1.5)
Step-by-step explanation:
x-intercept is the x-value when y = 0
y-intercept is the y-value when x = 0
Step 1: Find x-intercept
0 = (x - 3)/2
0 = x - 3
x = 3
(3, 0)
Step 2: Find y-intercept
y = (0 - 3)/2
y = -3/2
(0, -1.5)
