Answer:
The central blue square in between the lower pair of magnet has the least force of repulsion.
Explanation:
We can explain this using the dual nature of magnets.
Each magnet must have two poles namely:
-North pole
-South pole
We assume that the magnetic lines of forces enters from south pole and leaves from the north pole.
When brought together, like poles repel each other while opposite poles attract each other.
In the picture, the lower two magnets have opposite poles facing each other, hence the force of repulsion is minimum there and the force of attraction is maximum.
This question involves the concepts of th magnetic field and current.
The magnetic field created by the current at the house is "6.75 x 10⁻⁷ T".
<h3>Magnetic Field</h3>
The magnetic field created by a current carrying wire can be given by the following formula:
![B=\frac{\mu_o I}{2\pi r}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_o%20I%7D%7B2%5Cpi%20r%7D)
where,
- B = magnetic field = ?
= permeabiliy of free space =4π x 10⁻⁷- I = current = 152 A
- r = distance = 45 m
![B=\frac{4\pi x\ 10^{-7}(152)}{2\pi(45)}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B4%5Cpi%20x%5C%2010%5E%7B-7%7D%28152%29%7D%7B2%5Cpi%2845%29%7D)
B = 6.75 x 10⁻⁷ T
Learn more about magnetic field here:
brainly.com/question/23096032
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Answer:
Explanation:
To find Sammy's course you have to add the two velocities (vectors), 18 mph 327º and 4 mph 60º.
To add the two vectors analytically you decompose each vector into their vertical and horizontal components.
<u>1. 18 mph 327º</u>
- Horizontal component: 18 mph × cos (327º) = 15.10 mph
- Vertical component: 18 mph × sin (327º) = - 9.80 mph
![15.10\hat i-9.80\hat j](https://tex.z-dn.net/?f=15.10%5Chat%20i-9.80%5Chat%20j)
<u>2. 4 mph 60º</u>
- Horizontal component: 4 mph × cos (60º) = 2.00 mph
- Vertical component: 4 mph × sin (60º) = 3.46 mph
![2.00\hat i+3.46\hat j](https://tex.z-dn.net/?f=2.00%5Chat%20i%2B3.46%5Chat%20j)
<u>3. Addition:</u>
You add the corresponding components:
![15.10\hat i-9.80\hat j+2.00\hat i+3.46\hat j\\ \\ 17.10\hat i-6.34\hat j](https://tex.z-dn.net/?f=15.10%5Chat%20i-9.80%5Chat%20j%2B2.00%5Chat%20i%2B3.46%5Chat%20j%5C%5C%20%5C%5C%2017.10%5Chat%20i-6.34%5Chat%20j)
To find the magnitude use Pythagorean theorem:
<u>4. Direction:</u>
Use the tangent ratio:
Find the inverse: