Which graph set-up would enable students to calculate instantaneous acceleration from the slope on the graph? a) Place distance
1 answer:
Instantaneous acceleration is defined as rate of change in velocity
it is given by the equation
so here it shows that acceleration is always depends on change in velocity with time and now if we required this change in velocity with time for a small instant of time then it will be given by the slope of velocity and time graph.
So here the graph must be like this to find the slope of any graph we always use the concept that for any graph between y and x we use
if we compare it with the formula of acceleration above
then on Y axis we must have to draw the speed and on x axis we must have to draw the time
so correct answer must be
<u> d) Place time on the x-axis and velocity on the y-axis</u>
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Hi there!
(a)
Recall that:
W = Work (J)
F = Force (N)
d = Displacement (m)
Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.
To the nearest multiple of ten:
(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.
Thus:
(c)
Similarly, the normal force is perpendicular to the displacement, so:
(d)
Recall that the force of kinetic friction is given by:
Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
In multiples of ten:
(e)
Simply add up the above values of work to find the net work.
Nearest multiple of ten:
(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
Nearest multiple of ten: