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andrey2020 [161]
3 years ago
15

Which graph set-up would enable students to calculate instantaneous acceleration from the slope on the graph? a) Place distance

on the x-axis and time on the y-axis b) Place time on the x-axis and distance on the y-axis c) Place speed on the x-axis and distance on the y-axis d) Place time on the x-axis and velocity on the y-axis
Physics
1 answer:
Nataliya [291]3 years ago
6 0

Instantaneous acceleration is defined as rate of change in velocity

it is given by the equation

a = \frac{dv}{dt}

so here it shows that acceleration is always depends on change in velocity with time and now if we required this change in velocity with time for a small instant of time then it will be given by the slope of velocity and time graph.

So here the graph must be like this to find the slope of any graph we always use the concept that for any graph between y and x we use

slope = \frac{dy}{dx}

if we compare it with the formula of acceleration above

then on Y axis we must have to draw the speed and on x axis we must have to draw the time

so correct answer must be

<u> d) Place time on the x-axis and velocity on the y-axis</u>

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motikmotik

1)

first you find the maxium force that the car can produce.

f=ma

Fmax=(1100kg)(6m/s^2)

then use f = ma again to find the accel with the passengers

Fmax=(1100kg +1650kg)(a)

=> a = (1100kg)(6m/s^2)/( 1100kg +1650kg)

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3 years ago
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The Ha line of the Balmer series is emitted in the transition from n-3 to n 2. Compute the wavelength of this line for H and 2H.
Citrus2011 [14]

Explanation:

According to Rydberg's formula, the wavelength of the balmer series is given by:

\frac{1}{\lambda}=R(\frac{1}{2^2}-\frac{1}{3^2})

R is Rydberg constant for an especific hydrogen-like atom, we may calculate R for hydrogen and deuterium atoms from:

R=\frac{R_{\infty}}{(1+\frac{m_e}{M})}

Here, R_{\infty} is the "general" Rydberg constant, m_e is electron's mass and M is the mass of the atom nucleus

For hydrogen, we have, M=1.67*10^{-27}kg:

R_H=\frac{1.09737*10^7m^{-1}}{(1+\frac{9.11*10^{-31}kg}{1.67*10^{-27}kg})}\\R_H=1.09677*10^7m^{-1}

Now, we calculate the wavelength for hydrogen:

\frac{1}{\lambda}=R_H(\frac{1}{2^2}-\frac{1}{3^2})\\\lambda=[R_H(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=[1.0967*10^7m^{-1}(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=6.5646*10^{-7}m=656.46nm

For deuterium, we have M=2(1.67*10^{-27}kg):

R_D=\frac{1.09737*10^7m^{-1}}{(1+\frac{9.11*10^{-31}kg}{2*1.67*10^{-27}kg})}\\R_D=1.09707*10^7m^{-1}\\\\\lambda=[R_D(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=[1.09707*10^7m^{-1}(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=6.5629*10^{-7}=656.29nm

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3 years ago
You are travelling by skateboard at 3.0 m/s and start to accelerate. If you
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Answer: 8m/s

Explanation:

Vs= 3 m/s

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t=10s

-----------

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at=Vf-Vs

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5m/s+3m/s=Vf

Vf=8m/s

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PLEASE ANSWER!!! WILL GIVE BRAINLIEST!!!!!
Kipish [7]

Answer:

the ability to do work.

EXPLAINATION: .

in other words "the potential for causing changes" or "energy is the cause of any change" or "a work that a certain force *eg: gravitational* can do.

<em><u>sorry</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>wante</u></em><em><u>d</u></em><em><u> </u></em><em><u>but</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>couldn't </u></em><em><u>under</u></em><em><u>stand</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>that's </u></em><em><u>why</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>wrote</u></em><em><u> </u></em><em><u>what</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>understood</u></em><em><u>.</u></em>

6 0
2 years ago
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