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andrey2020 [161]
3 years ago
15

Which graph set-up would enable students to calculate instantaneous acceleration from the slope on the graph? a) Place distance

on the x-axis and time on the y-axis b) Place time on the x-axis and distance on the y-axis c) Place speed on the x-axis and distance on the y-axis d) Place time on the x-axis and velocity on the y-axis
Physics
1 answer:
Nataliya [291]3 years ago
6 0

Instantaneous acceleration is defined as rate of change in velocity

it is given by the equation

a = \frac{dv}{dt}

so here it shows that acceleration is always depends on change in velocity with time and now if we required this change in velocity with time for a small instant of time then it will be given by the slope of velocity and time graph.

So here the graph must be like this to find the slope of any graph we always use the concept that for any graph between y and x we use

slope = \frac{dy}{dx}

if we compare it with the formula of acceleration above

then on Y axis we must have to draw the speed and on x axis we must have to draw the time

so correct answer must be

<u> d) Place time on the x-axis and velocity on the y-axis</u>

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In an arithmetic progression, consecutive terms differ by the same value.

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A rigid tank contains nitrogen gas at 227 °C and 100 kPa gage. The gas is heated until the gage pressure reads 250 kPa. If the a
aleksley [76]

Answer:

 T₂ =602  °C

Explanation:

Given that

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P₁ = 100 + 100 KPa

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Gauge pressure at condition 2 given = 250 KPa

The absolute pressure at condition 2 will be

P₂ = 250 + 100 KPa

P₂ =350 KPa

The temperature at condition 2 = T₂

We know that

\dfrac{T_2}{T_1}=\dfrac{P_2}{P_1}\\T_2=T_1\times \dfrac{P_2}{P_1}\\T_2=500\times \dfrac{350}{200}\ K\\

T₂ = 875 K

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Lelu [443]

Answer:

Radius of the loop is 0.18 m or 18 cm

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Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T

Number of turns in circular wire, N = 1

Consider R be the radius of the circular wire.

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Substitute the suitable values in the above equation.

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