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Rainbow [258]
2 years ago
14

A motorcyclist is traveling at a speed of 72 km/h along a straight road. If the motorcyclist can slow down at a rate of 2 m/s2,

what is the minimum stopping distance the motorcyclist needs?
Physics
1 answer:
andriy [413]2 years ago
4 0

Answer:

A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. How much time is required for the car to reach a speed of 90 km/h? (4.2 s).

i think this is it

Explanation:

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The 10-lb block has a speed of 4 ft/s when the force of f=(8t2)f=(8t2) lb is applied. determine the velocity of the block when t
KatRina [158]

The velocity of the block when t == 2 s is 60.7 ft./sec.

Equations of Motion.

Here the friction is F_f = \mu_k N = 0.2 N

+ \uparrow \sum F_y = ma_y; \quad N – 10 = \frac { 10 } { 32.2 }(0) \quad N = 10 lb \\ \begin{aligned} \underrightarrow{ + } \sum F_x = ma_x; \quad 8t^2 – 0.2(10 &) = \frac { 10 } { 32.2 }a \\ & a = 3.22(8t^2 – 2) ft/s^2 \end{aligned}

Kinematics.

The velocity of the block as a function of t can be determined by

integrating dv = adt using the initial condition v = 4 ft./s at t = 0.

\int_{ 4 ft/s }^{ v } dv = \int_0^t 3.22(8t^2 – 2)dt \\ \begin{aligned} v – &4 = 3.22 (\frac 8 3 t^3 – 2t) \\ & v = \{8.5867t^3 – 6.44t + 4 \} ft/s \end{aligned}

The displacement as a function of t can be determined by integrating

ds = vdt using

the initial condition s = 0 at t = 0

\int_0^s ds = \int_0^t (8.5867t^3 – 6.44t + 4)dt \\ s = \{2.1467t^4 – 3.22t^2 + 4t \} ft

at t = 2 sec

s = 30 ft.

Thus, at s = 30 ft.,

\begin{aligned} v &= 8.5867(2.0089^3) – 6.44(2.0089) + 4 \\ &= 60.67 ft/s \\ &= 60.7 ft/s \end{aligned}

Kinematics is a subfield of physics, developed in classical mechanics, that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the forces that cause them to move.

Kinematics, as a field of study, is often referred to as the "geometry of motion" and is occasionally seen as a branch of mathematics. A kinematics problem begins by describing the geometry of the system and declaring the initial conditions of any known values of position, velocity and/or acceleration of points within the system.

Then, using arguments from geometry, the position, velocity and acceleration of any unknown parts of the system can be determined. The study of how forces act on bodies falls within kinetics, not kinematics. For further details, see analytical dynamics.

Learn more about kinematics here : brainly.com/question/24486060

#SPJ4

5 0
11 months ago
What angle will give you the maximum range (horizontal displacementon a projectile? ( 3 pts)
natulia [17]

Answer:

45 degrees

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

8 0
2 years ago
Will mark as brainliest if correct!!!!!
irakobra [83]

Refraction refers to C. the bending of light rays when they pass from one medium into another

Explanation:

Refraction is a phenomenon typical of wave. Refraction occurs when a wave travels through the boundary between two different mediums. When this occurs, the wave changes speed, wavelength and direction (but the frequency remains the same).

In particular, the direction of the refracted ray is determined by Snell's Law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1 is the index of refraction of the 1st medium

n_2 is the index of refraction of the 2nd medium

\theta_1 is the angle of incidence, which is the angle between the direction of the incident wave and the normal to the boundary

\theta_2 is the angle of refraction, which is the angle between the direction of the refracted wave and the normal to the boundary

Therefore, the correct description of refraction is

C. the bending of light rays when they pass from one medium into another

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

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8 0
3 years ago
Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?
worty [1.4K]

Answer:Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

A. Reducing its mass to one-half of its original value

B. Increasing its velocitato twice its original value

C. Reducing its velocity to one-half of its original value O

D. Increasing its mass to twice its original value ​Questlon 20 of 20 Which change to an object would quadruple its kinetic energy?

Explanation:

6 0
2 years ago
Read 2 more answers
A train travels 120 km In 2 hours and 30 minutes what’s its average speed
dangina [55]
Formula for distance is d=st
so for speed is s=d/t 
 48 km per hour
8 0
3 years ago
Read 2 more answers
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