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Rainbow [258]
2 years ago
14

A motorcyclist is traveling at a speed of 72 km/h along a straight road. If the motorcyclist can slow down at a rate of 2 m/s2,

what is the minimum stopping distance the motorcyclist needs?
Physics
1 answer:
andriy [413]2 years ago
4 0

Answer:

A car initially traveling at 60 km/h accelerates at a constant rate of 2.0 m/s2. How much time is required for the car to reach a speed of 90 km/h? (4.2 s).

i think this is it

Explanation:

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A force of 25 newtons moves a box a distance of 4 meters in 5 seconds.
Simora [160]

By definition, we have that the work done is given by:

W = F * d

Where,

F: force in the direction of displacement

d: displaced distance

Substituting values we have:

W = (25) * (4)\\W = 100 Nm

Then, the power is given by:

P = \frac{W}{t}

Where,

t: time

Substituting values we have:

P = \frac{100}{5}

P = 20\frac{Nm}{s}

Answer:

The work done on the box is 100 Nm, and the power is 20 Nm/s.

5 0
3 years ago
Read 2 more answers
How does gravity affect maglev trains?
yuradex [85]
Earth pulls it downward to the gravitational force
3 0
3 years ago
A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 poin
Musya8 [376]

Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude <em>y</em> at time <em>t</em> is

y(t)=50\,\mathrm m-\dfrac12gt^2

where <em>g</em> = 9.80 m/s^2 is the acceleration due to gravity.

The ball hits the ground when <em>y</em> = 0:

0 = 50\,\mathrm m-\dfrac12gt^2

t^2=\dfrac{100\,\mathrm m}g

t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}

6 0
3 years ago
Wait so if dogs can eat human food why can't humans eat dog food?
NemiM [27]
Because animals are animals and humans hopefully don’t want to be treated like animals, also it is preferred that they don’t eat human food like gum or chocolate…
7 0
3 years ago
Read 2 more answers
forces of 3.0 N (west) and 4.0 N (33° S of E) act on an object. What is the net force of the object? Calculate both magnitude an
alexandr402 [8]

The net force is 2.2 N at 80.9 degrees south of east

Explanation:

In order to find the net force, we have to resolve each force along the x-y direction, and then add the components in each direction.

Taking east as positive x-direction and north as positive y-direction, we have:

- First force:

F_{1x} = -3.0 N\\F_{1y} = 0

- Second force:

F_{2x} = (4.0)(cos (-33^{\circ})=3.35 N\\F_{2y} = (4.0)(sin (-33^{\circ})=-2.18 N

Therefore, the components of the net force are

F_x = F_{1x}+F_{2x}=-3.0+3.35=+0.35 N\\F_y = F_{1y}+F_{2y}=0+(-2.18)=-2.18 N

And so, the magnitude of the net force is

F=\sqrt{F_x^2+F_y^2}=\sqrt{(0.35)^2+(-2.18)^2}=2.2 N

And the direction is

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-2.18}{0.35})=-80.9^{\circ}

which means 80.9 degrees south of east.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

6 0
3 years ago
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