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2 years ago

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if force accelerate mass with acceleration and the same force accelerate the mass which is quarter of the first one by

1 answer:

Degger [83]2 years ago

4 0

Answer:

loveveeeeueufurjbfuuendbbsvegbdb

Explanation:

hdhdbduxnrbdbsnsjjejfndnerf

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What kind of image does the lens in a camera produce? real and upside down real and right-side up virtual and upside down virtua

Vlada [557]

Answer:

<u>real and upside down </u>

Explanation:

Lens of a camera gathers light and focuses it on the light detector or film strip. <u>A real and inverted (upside -down) image is formed. </u>This image is then stored and processed and inverted. Thereafter we see an upright image. A chemical reaction on the film strip stores the image. In a digital lens, a light detector such as CCD stores the image.

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2 years ago

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A red cart has a mass of 4 kg and a velocity of 5 m/s. There is a 2-kg blue cart that is parked and not moving, thus its velocit

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3 years ago

A uniform electric ﬁeld exists in the region between two oppositely charged plane-parallel plates. An electron is released from

Zigmanuir [339]

Answer:

Explanation:

given S = distance from the first = 3.20cm = 0.032m, t = 1.30×10−8 s

q = 1.6 x 10_19C

using S = at^2/2

acceleration = 0.032 X 2 /(1.30×10−8)^2

a = 3.79 x 10^14m/s^2

From F = ma

F = qE

ma = qE

E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19

E = magnitude of this electric ﬁeld. = 2156.3N/C

b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as

= 2 X 3.79 x 10^14 X 0.032

= 4.92 X 10^6m/s

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2 years ago

What is the Sl unit for momentum?<br> O kg• m<br> O kg<br> O kg• m<br> O kg<br> 2<br> m

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Explanation:

<h2><em>The </em><em>S. </em><em>I. </em><em> </em><em>unit </em><em>of </em><em>momentum </em><em>is </em><em>Kg. </em><em>m/</em><em>s</em><em>e</em><em>c</em></h2>

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2 years ago

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.460 Hz. The pendulum ha

zlopas [31]

Answer:

The moment of inertia is $I =1.0697 \ kg m^2$

Explanation:

From the question we are told that

The frequency is $f = 0.460 \ Hz$

The mass of the pendulum is $m = 2.40 \ kg$

The location of the pivot from the center is $d = 0.380 \ m$

Generally the period of the simple harmonic motion is mathematically represented as

$T = 2 \pi * \sqrt{ \frac{I}{ m * g * d } }$

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it

=> $I = [ \frac{T}{2 \pi } ]^2 * m* g * d$

But the period of this simple harmonic motion can also be represented mathematically as

$T = \frac{1}{f}$

substituting values

$T = \frac{1}{0.460}$

$T = 2.174 \ s$

So

$I = [ \frac{2.174}{2 * 3.142 } ]^2 * 2.40* 9.8 * 0.380$

$I =1.0697 \ kg m^2$

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2 years ago