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harkovskaia [24]
3 years ago
7

In a circle with a radius of 36 3/5  cm, an arc is intercepted by a central angle of 2π/7 radians.   What is the arc length? Use

3.14 for π and round your final answer to the nearest hundredth. Enter your answer as a decimal in the box.
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0
Just took the quiz.

The answer is 32.84
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Evaluate the given integral by making an appropriate change of variables, where r is the rectangle enclosed by the lines x - y =
vova2212 [387]
\begin{cases}u=x-y\\v=x+y\end{cases}

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial u}{\partial y}\\\\\dfrac{\partial v}{\partial x}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&-1\\1&1\end{bmatrix}
\implies\det\mathbf J=2

The area of the region is then given by

\displaystyle\iint_R\mathrm dA=\int_{u=0}^{u=7}\int_{v=0}^{v=6}2\,\mathrm dv\,\mathrm du=84
6 0
3 years ago
The Graph to answer the questions
dedylja [7]

123456789101112131415

5 0
2 years ago
You deposit a lump sum today that in 8 years from now will be worth $17000. If the deposit earns 4% compounded quarterly. What's
Sophie [7]
Using the compound interest formula,

A = P(1+r)^n

A = 17000

r = 4% quarterly

n = 8yrs = 32 quarters of a year

P = ?

17000 = P(1+4%)^32

P = $[17000/((1+4%)^32)]

6 0
2 years ago
How much larger is 8 in 8237 and 8 in 823.7
balandron [24]
Since the 8 in the first number is in the thousands place, its value it 8*1000=8000.
Since the 8 in the second number is in the hundreds place, its value is 8*100=800.

8000 is ten times 800.
Final answer: 10x as large
8 0
3 years ago
Read 2 more answers
The data below indicate the time (in seconds) that it takes 25 separate employees to complete a certain task. hw1_q5.csva) What
IgorC [24]

Answer:

Explained below.

Step-by-step explanation:

Consider the data provided.

(a)

Compute the mean of the data in seconds as follows:

Mean =AVERAGE(array)

         = 225.280 seconds

(b)

Compute the median of the data in seconds as follows:

Median =QUARTILE.EXC(array,2)

            = 229 seconds

(c)

Compute the variance of the data in seconds as follows:

Variance =VAR.S(array)

              = 1148.043 seconds

(d)

Compute the standard deviation of the data in seconds as follows:

Standard deviation =STDEV.S(F2:F26)

                              = 33.883 seconds.

(e)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

            = 3.755 minutes.

(f)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

            = 3.817 minutes

(g)

Compute the variance of the data in minutes as follows:

Variance =VAR.S(array)

              = 0.319 minutes

(h)

Compute the standard deviation of the data in minutes as follows:

Standard deviation =STDEV.S(F2:F26)

                              = 0.565 minutes.

3 0
3 years ago
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