Answer:
B, i think.
Explanation:
Calculate the number of moles of solute present.
Moles of Na0H =15.0g Na0H x 1 molNa0H over 40.00g Na0H= 0.375 mol Na0H.
Calculate the liters of solution present.
volume=225mL x iL over 1000mL = 0.225 L soln
Divide the number of moles of solute by the number of liters of solution.
Molarity= 0.375mol over 0.225L =1.67 mol/L
Ec₁=mv₁²/2=450*26²/2=225*676=152100 J
Ec₂=mv₂²/2=450*30²/2=225*900=202500 J
ΔEc=Ec₂-Ec₁=202500-152100=50.4 kJ
The first choice Always given to you by other people
I hope this helped :3
Answer:
Yo soy religioso y no creo en la ciencia.
Los que si creen el la ciencia no creen el la religion.
Y asi susesivamente