A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end
1 answer:
The magnitude of the tension in the string is 9.31 N.
<h3>Tension in the string</h3>The magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;
T = Fcos(θ)
where;
- F is centripetal force
- θ is inclination of the string
Thus, the magnitude of the tension in the string is 9.31 N.
The complete question is below:
A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.
Learn more about tension in horizontal circle here: brainly.com/question/12803719
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Answer:
a) and b)
Explanation:
We have to analyze this problem from the point of view of energy conservation. In this case there are two kind of energy, electric potential energy and kinetic energy. First, at there isn't relative movement between the two charges, so kinetic energy is zero and the total energy (
) is just potential.
where is the Coulomb constant,
and
are the two interacting charges, and
is the distance between them.
Considering the fixed charge at (x1,y1) = (0,0) and the second one at (x2, y2) = (1.25, 0.57), the initial distance is
, then if
and
,
.
Now, at ,
and
. This means all the energy is kinetic
, so
(mass in Kg).
That would be the velocity when the second charge moves infinitely far from the origin.
For the second part we have that , so kinetic energy is
and potential energy is
so the distance is