Question

A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine:

Answer 1

The magnitude of the tension in the string is 9.31 N.

Tension in the string

The magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;

T = Fcos(θ)

where;

• F is centripetal force
• θ is inclination of the string

$T = \frac{mv^2}{r} \times cos(\theta)\\\\T = \frac{3 \times 4.5^2}{5} \times cos(40)\\\\T = 9.31 \ N$

Thus, the magnitude of the tension in the string is 9.31 N.

The complete question is below:

A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.

Learn more about tension in horizontal circle here: brainly.com/question/12803719