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2 years ago

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A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end

of a 5.00 m - long string (L). If theta = 40.0o,determine:

1 answer:

navik [9.2K]2 years ago

4 0

The magnitude of the tension in the string is 9.31 N.

<h3>Tension in the string</h3>

The magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;

T = Fcos(θ)

where;

F is centripetal force
θ is inclination of the string

$T = \frac{mv^2}{r} \times cos(\theta)\\\\T = \frac{3 \times 4.5^2}{5} \times cos(40)\\\\T = 9.31 \ N$

Thus, the magnitude of the tension in the string is 9.31 N.

The complete question is below:

A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.

Learn more about tension in horizontal circle here: brainly.com/question/12803719

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