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3 years ago

Which solution is the most concentrated?

Physics

1 answer:

tekilochka [14]3 years ago

8 0

Answer:

B, i think.

Explanation:

Calculate the number of moles of solute present.

Moles of Na0H =15.0g Na0H x 1 molNa0H over 40.00g Na0H= 0.375 mol Na0H.

Calculate the liters of solution present.

volume=225mL x iL over 1000mL = 0.225 L soln

Divide the number of moles of solute by the number of liters of solution.

Molarity= 0.375mol over 0.225L =1.67 mol/L

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A bullet with a mass ????b=13.5mb=13.5 g is fired into a block of wood at velocity ????b=253vb=253 m/s. The block is attached to

Lorico [155]

Answer:

450 grams

Explanation:

Given:

mass of the bullet, m = 13.5 g = 0.0135 kg

velocity of the bullet, v = 253 m/s

spring constant of the spring, k = 205 N/m

Compression of the spring, x = 35.0 cm = 0.35 m

Now, the kinetic energy of the moving system (bullet + board) will tend to move the spring

thus,

let velocity of the system, V

now, applying the concept of conservation of momentum, we have

mv = (M + m)V

where,

M is the mass of the block

thus,

V = mv/(M + m)

now,

the kinetic energy of the system = (1/2)(M + m)V²

the kinetic energy of the system = (1/2)(M + m)(mv/(m + M))²

Energy gained by the spring = (1/2)kx²

now,

equating both the energies, we get

(1/2)(M + m)(mv/(m + M))² = (1/2)kx²

(mv)²/(m + M) = kx²

on substituting the values, we get

(0.0135 × 253)²/(0.0135 + M) = 205 × (0.35)²

11.66/(0.0135 + M) = 25.1125

M = 0.450 kg = 450 grams

8 0

3 years ago

A person is spinning an object around on a circular path on the end of a string of length 0.96 m. The object has a mass of 0.34

Rama09 [41]

I’m so sorry I needed points but I hope you get it right

8 0

3 years ago

3) A driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. If the coefticient of friction between

Natali5045456 [20]

Answer:

A) 37 m

Explanation:

The car is moving of uniformly accelerated motion, so the distance it covers can be calculated by using the following SUVAT equation:

$v^2 -u^2 = 2ad$ (1)

where

v = 0 m/s is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d is the length of the skid

We need to find the acceleration first. We know that the force responsible for the (de)celeration is the force of friction, so:

$F=ma=-\mu mg$

where

m = 1000 kg is the mass of the car

$\mu = 0.80$ is the coefficient of friction

a is the deceleration of the car

g = 9.8 m/s^2 is the acceleration due to gravity

The negative sign is due to the fact that the force of friction is against the motion of the car, so the sign of the acceleration will be negative because the car is slowing down. From this equation, we find:

$a=-\mu g$

And we can substitute it into eq.(1) to find d:

$v^2 -u^2 = 2(\-mu g) d\\d= \frac{v^2-u^2}{-2 \mu g}=\frac{0-(24 m/s)^2}{-2(0.80)(9.8 m/s^2)}=36.7 m \sim 37 m$

7 0

3 years ago

Give a real-world example of how energy is transformed from electrical energy to thermal energy. Describe how the heat can be tr

timofeeve [1]

Answer:

A microwave

Explanation:

Car

Lightbulb is a really good one

Same with the sun. That one has Chemical as well

3 0

2 years ago

A bullet travels at 850 m/s. how long will it take a bullet to go 1 km?

Dmitrij [34]

The speed of bullet =
850 m/s

Distance given = 1 km = 1000m

S = D/t
t • S = D/t • t
St = D
St/S = D/S
t = D/S
t = 1000m/850m/s
t = 1.176 s

It will take the bullet 1.176 or about 1.18 seconds to go 1 km.

8 0

3 years ago