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lutik1710 [3]
3 years ago
10

What do we mean by principle of conservation?​

Physics
1 answer:
leonid [27]3 years ago
7 0

Answer:

Conservation principles tell us that some<u> quantity, quality, or aspect remains constant through change. </u>

Explanation:

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The alarm at a fire station rings and a 87.5-kg fireman, starting from rest, slides down a pole to the floor below (a distance o
blsea [12.9K]

Answer:

F_f=840N

Explanation:

From the question we are told that

Weight of fireman W_f= 87.5kg

Pole distance D=4.10m

Final speed is V_f 1.75m/s

Generally the equation for velocity is mathematically represented as

v^2 = v_0^2 + 2 a d

Therefore Acceleration a

a'= v^2 / 2 d

a'= 0.21m/s^2

Generally the equation for Frictional force F_f is mathematically given as

F_f=m*a

F_f=m*(g-0.21)

F_f=87.5*(9.81-0.21)

Therefore

F_f=840N

6 0
3 years ago
if grapefruit juice has a ph of 3.0 and egg white have a ph of 8.0, which contains more h+ ions ? how many more ?
hammer [34]
Grapefruit juice. The more acidic something is the more h it has. 
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3 years ago
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A person jumped off a cliff, what would happen?
Anastaziya [24]
Death would happen, hope this helped
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2 years ago
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What is the most appropriate SI unit to express the speed of a cyclist in a 10-km race?
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Your answer should be A.km/s does s mean speed?
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4 years ago
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4.72 A full-wave bridge-rectifier circuit with a 1-k load operates from a 120-V (rms) 60-Hz household supply through a 12-to-1 s
melisa1 [442]

Answer:

a) 12.74 V

b) Two pairs of diode will work only half of the cycle

c) 8.11 V

d) 8.11 mA

Explanation:

The voltage after the transformer is relationated with the transformer relationshinp:

V_o=Vrms*\frac{1}{12}\\V_o=10Vrms

the peak voltage before the bridge rectifier is given by:

V_{op}=Vo*\sqrt{2}\\V_{op}=14.14V

The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:

V_l=V_{op}-2(0.7)\\V_l=12.74V

As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.

The averague voltage on a full wave rectifier is given by:

V_{avg}=2*\frac{V_l}{\pi}\\V_{avg}=8.11V

Using Ohm's law:

I_{avg}=\frac{V_{avg}}{R}\\\\I_{avg}=8.11mA

7 0
3 years ago
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