Very bad written question
C, then, D, A
Answer:
c. 3
Explanation:
The unbalanced reaction expression is given as:
Fe + O₂ → Fe₂O₃
To balance the expression gives the coefficient of oxygen.
Assign the coefficients a,b, c and use a mathematical approach to solve this problem:
aFe + bO₂ → cFe₂O₃
Conserving Fe: a = 2c
O: 2b = 3c
Now let c = 1, a = 2, b = 
Multiply through by 2,
a = 4, b = 3 and c = 2
4Fe + 3O₂ → 2Fe₂O₃
The coefficient of O₂ is 3
Answer:
42.24 psi.
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 29.72 psi
Initial volume (V₁) = 10.22 L
Final volume (V₂) = 7.19 L
Final pressure (P₂) =?
The final pressure can be obtained by applying the Boyle's law equation as follow:
P₁V₁ = P₂V₂
29.72 × 10.22 = P₂ × 7.19
303.7384 = P₂ × 7.19
Divide both side by 7.19
P₂ = 303.7384 / 7.19
P₂ = 42.24 psi
Therefore, the final pressure is 42.24 psi
The mass of ethanol present in the vapor is 8.8×10⁻²g. when liquid and vapor ethanol at equilibrium.
The volume of the bottle = 4.7 L
Mass of ethanol = 0.33 g
Temperature (T1) = -11 oC = 273-11 = 262 K
P1 = 6.65 torr
Now we will calculate the mole by applying the ideal gas equation:-
PV = nRT
Or, n = PV/RT
Where P is the pressure
T is the temperature
R is the gas constant = 0.0821 L atm mol-1K-1
V is the volume
Substituting the values of P, V, T, and R the mole of ethanol is calculated as:-
= 0.001913 mol C2H6
Conversion of the mole to gm
Molar mass of ethanol (M) = 46.07 g/mol
Mass of C2H6O =0.001913 mol C2H6O 46.07 g/mol = 0.088 = 8.8×10⁻²g.
Hence, the mass of ethanol present in the vapor is found to be 8.8×10⁻²g.
Learn more about mole here:-brainly.com/question/15374113
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Answer:
1000 gram
Explanation:
because mass is constant everywhere
