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yulyashka [42]
3 years ago
11

The wax appears to disappear as a candle burns. How can the law of conservation of mass apply to this reaction?

Chemistry
1 answer:
White raven [17]3 years ago
8 0
Because mass is neither created nor destroyed, so the wax can not just disappear.
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The following equation represents the type of reaction called
Mazyrski [523]

Answer:

Reduction

Explanation:

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Mn⁺⁷ +3e⁻    →    Mn⁴⁺

Mn gets three electrons , its oxidation state reduced from +7 to +4 so Mn gets reduced.

Examples:

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

6 0
3 years ago
What is the pH of a 0.00001 M solution of HCI?
ale4655 [162]

Answer:

0.00001= 1 x 10^-5. Since HCl is an acid, 1 x10^-5 is the H+ concentration. Write only the number of the exponent. Therefore, pH = 5.

5 0
3 years ago
Which of the following happens when solid sodium chloride dissolves in water?A.The attractive forces between water and the sodiu
grin007 [14]

Answer: option D. The attractive forces between the sodium and chloride ions are overcome by the attractive forces between the water and the sodium and chloride ions.

Explanation:

<em>Solid sodium chloride</em> (NaCl) is a ionic compound formed by ionic bonds between by the positive, metallic cations of sodium atom, Na⁺, and the negative, non-meatllic anions of chlorine atom, Cl⁻ (chloride).

Ionic bonds, then, are the electrostatic attracion between oppositely charged particles (cations and anions).

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<em>When solid sodium chloride dissolves in water</em>, the ions (cations and anions) are separated in the solvent (water) due to the superior attracitve forces between such ions and the polar water molecules.

<em>Water</em> (H₂O) is a molecule, formed by polar covalent bonds between two hydrogen atoms and one oxygen atom.

The polarity of water molecule is due to the fact that oxygen atoms are more electronegative than hydrogen atoms, which cause that the electron density is closer to oxygen nuclei than to hydrogen nuclei. This asymmetry in the electron density conferes a partial positive charge over each hydrogen atom and a partial negative charge over the oxygen atoms.

Thus, the positively charged hydrogen atoms attract and surround the negative chloride (Cl⁻) anions, while the negatively charged oxygen atoms attract and surround the positive sodium (Na⁺) cations. It is only because the attractive forces between the water and the sodium and chloride ions are stronger than the attractive forces between the sodiium and chloride ions that such ions may be kept separated in the solution. This process is called solvation and the ions are said to be solvated by the water molecules.

7 0
3 years ago
When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?
stepladder [879]

Answer:

m_{precipitated}=24.8g

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g

Best regards.

8 0
3 years ago
Draw one of the stereoisomers of the product formed when benzaldehyde (c6h5cho) is treated with ph3p═chcooch3.
8_murik_8 [283]
This reaction is known as Wittig Reaction. A powerful reaction for the synthesis of Alkene. In question the starting materials are aldehyde and a Phosphorous Ylide. Ylide when reacted with aldehyde produces a four membered ring which on rearrangement gives Alkene and triphenylphosphine oxide. Phosphorous having great affinity toward the oxygen is the driving force of this rearrangement. The reaction along with product (highlighted blue) is as follow,

8 0
4 years ago
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