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____ [38]
2 years ago
9

How many moles are there in 5.699 liters of neon gas at STP? Express your answer with the appropriate significant figures and un

it.
Chemistry
1 answer:
Svetradugi [14.3K]2 years ago
4 0

Answer:

The number of moles: 0.25442 moles

Explanation:

One mole of Neon gas will occupy 22.4 at STP.

5.699L consists of \frac{5.699}{22.4} = 0.25442 moles.

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What is the source of the electrons produced in beta decay
Vitek1552 [10]

Answer:

Beta rays are electrons.

Explanation:

A neutron in the nucleus of  a radioactive atom decays into a proton and an electron, which is emitted from the atom.

8 0
3 years ago
URGENT !! A substance has 55.80% carbon, 7.04% Hydrogen, and 37.16% Oxygen. What is it's empirical and molecular formula if it h
Ede4ka [16]
<h3><u>Answer;</u></h3>

Empirical formula = C₂H₃O

Molecular formula = C₁₄H₂₁O₇

<h3><u>Explanation</u>;</h3>

Empirical formula

Moles of;

Carbon = 55.8 /12 = 4.65 moles

Hydrogen = 7.04/ 1 = 7.04 moles

Oxygen  = 37.16/ 16 = 2.3225 moles

We then get the mole ratio;

4.65/2.3225 = 2.0

7.04/2.3225 = 3.0

2.3225/2.3225 = 1.0

Therefore;

The empirical formula = <u>C₂H₃O</u>

Molecular formula;

(C2H3O)n = 301.35 g

(12 ×2 + 3× 1 + 16×1)n = 301.35

43n = 301.35

  n = 7

Therefore;

Molecular formula = (C2H3O)7

                             <u> = C₁₄H₂₁O₇</u>

6 0
3 years ago
Type the CONVERSION factor (fraction) to calculate the moles in 15.0 g
kari74 [83]

Explanation:

5g C7H8 / 92g/mole = 0.054moles

total moles = 0.232moles

mole fraction C6H12 = 0.178moles / 0.232moles = 0.767

mole fraction C7H8 = 0.233

6 0
3 years ago
Consider the elements bromine and chlorine; which element has a larger ionic radius?
Nikolay [14]
Not 100% be Im pretty positve its Bromine

6 0
3 years ago
Read 2 more answers
A solution containing 0.050 g of an unknown nonelectrolyte in 2.50 g of cyclohexane (Kf = 20.4 oC/m &amp; F.P. 6.6 oC) was found
ANEK [815]

Answer:

The molar mass of the unknown substance is 255g/mole

Explanation:

Freezing point depression is given by

ΔT = i · Kf · m

Where

m = molality of the solute

i = van't Hoff's factor = i for non electrolyte

Kf = 20.4 °C/m = cryoscopic constant

ΔT = Freezing point depression

Therefore ΔT = 6.6 - 5 = 1.6 °C

1.6 °C = 20.4 °C/m × 1 × m

Therefore m = 1.6/20.4 = 0.0784 m

number of moles in 2.50 g of cyclohexane = 0.0784 m or 0.0784 moles of the substance in 1000 grams of cyclohexane. That is

2.5 ×0.0784/1000 moles in 2.5 graams of cyclohexane  that is

1.96 × 10⁻⁵ moles in 2.5 grams of cyclohexane

1.96 × 10⁻⁵ moles of the substance weighs 0.050 grams

Therefore 1 Mole weighs (0.05 g)/(1.96 × 10⁻⁵ moles) = 255g/mole

7 0
3 years ago
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