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Licemer1 [7]
3 years ago
12

A mixture was found to contain 3.50 g of sugar, 4.80 g of NaCl, and 7.20 g of sand. What is the percentage of sand?

Chemistry
1 answer:
lozanna [386]3 years ago
4 0

First get the sum of the mass of each substance.

total mass = 3.50 g + 4.80 g + 7.20 g

total mass = 15.50 g

 

The percentage mass would be:

% mass = (7.20 g / 15.50 g) * 100%

<span>% mass = 46.45%</span>

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C12H7Cl3FNaO2 what are them elements in that chemical formula
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8 0
4 years ago
How many moles are in 4177g of aluminum chloride
Luden [163]
The mole<span> is the </span>unit of measurement<span> in the </span>International System of Units<span> (SI) for </span>amount of substance<span>. It is defined as the </span>amount<span> of a </span>chemical substance<span> that contains as many representative particles, e.g., </span>atoms<span>, </span>molecules<span>, </span>ions<span>, </span>electrons<span>, or </span>photons<span>, as there are atoms in 12 </span>grams<span> of </span>carbon-12<span> (</span>12<span>C), the </span>isotope<span> of </span>carbon<span> with </span>relative atomic mass<span> 12 by definition. 
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4 0
3 years ago
**Plz help with this asap who ever replies first with the right answer will get brainlists
Vesna [10]

Answer:first D. 88L

Second A 2*10^24

Explanation:

At stp 1 mole = 22.4L

mw Cl2= 70.9

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aw Sr 87.6 —> 6.02214076*10^23 atoms = 1 mole

5 0
3 years ago
A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calc
disa [49]

Answer:

specific heat = 0.951 j/g·°C

Explanation:

Heat flow equation  => q = m·c·ΔT

q = heat flow = 4817 joules

m = mass in grams = 140 grams Aluminum

c = specific heat = ?

ΔT = Temperature Change in °C = 98.4°C - 62.2°C = 36.2°C

q = m·c·ΔT => c = q/m·ΔT = 4817j/(140g)(36.2°C) = 0.951 j/g·°C

6 0
3 years ago
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