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marshall27 [118]
4 years ago
14

The nutritional information on a cereal box shows that one serving of dry cereal has 90 calories (actually kilocalories). If one

were to burn a serving of cereal, the amount of heat given off would be sufficient to raise the temperature of 1 kg of water in how many degrees Celsius?
Chemistry
1 answer:
umka2103 [35]4 years ago
5 0

Answer:

90 °C

Explanation:

First, we must know the specific heat capacity of water, which is defined as the energy required to heat 1 gram of water by one degree Celsius. The specific heat capacity of water is 1 cal·g⁻¹°C⁻¹.

The equation we will use is Q = mcΔt, where Q is the heat energy, m is the mass, c is the specific heat capacity, and Δt is the temperature change. We will rearrange the equation to solve for Δt and substitute the values:

Δt = Q / (mc) = (90 kcal)(1000 cal/kcal) / (1 kg)(1000 g/kg)(1 cal·g⁻¹°C⁻¹) = 90 °C

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Solid aluminum and gaseous oxygen read in a combination reaction to produce aluminum oxide. 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3
Kryger [21]

Answer:

4.7 g. Option 5 is the right one.

Explanation:

4Al(s) + 3O₂ (g) ⇄ 2Al₂O₃ (s)

We convert the mass of reactants to moles, in order to determine the limiting.

2.5 g Al / 26.98 g/mol → 0.092 moles of Al

2.5 g O₂ / 32g/mol → 0.078 moles of O₂

Ratio is 4:3. 4 moles of Al react with 3 moles of O₂

Then, 0.092 moles of O₂ would react with (0.092 . 3)/ 4 = 0.069 moles O₂

We have 0.078 moles of O₂ and we need 0.069 moles, the oxygen is the limiting in excess. Therefore the Al is the limiting reactant.

Ratio is 4:2. 4 moles of Al, can produce 2 moles of Al₂O₃

Then, 0.092 moles of Al would produce (0.092 .2) / 4 = 0.046 moles

If we convert the moles to mass, we find the anwer:

0.046 mol . 101.96 g/mol = 4.69 g

5 0
3 years ago
g Enter your answer in the provided box. If 30.8 mL of lead(II) nitrate solution reacts completely with excess sodium iodide sol
Ronch [10]

Answer:

M=0.0637M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Pb(NO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaNO_3(aq)

Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:

n_{Pb^{2+}}=0.904gPbI_2*\frac{1molPbI_2}{461gPbI_2}*\frac{1molPb(NO_3)_2}{1molPbI_2}  *\frac{1molPb^{2+}}{1molPb(NO_3)_2} =1.96x10^{-3}molPb^{2+}

Finally, the resulting molarity in 30.8 mL (0.0308 L):

M=\frac{1.96x10^{-3}molPb^{2+}}{0.0308L}\\ \\M=0.0637M

Regards.

3 0
3 years ago
02:22:18
Artemon [7]

Answer: b design procedure

Explanation:

design a procedure

7 0
3 years ago
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NEED HELP ASAP! Write a statement explaining your claim about whether or not the equation is correctly balanced.
cupoosta [38]

Answer:

I think that it it correctly balanced that is my opinion and, because  the way it is set up, that the answer will tell you weather or not it is correctly balanced or not.

8 0
2 years ago
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Silicon reacts with carbon dioxide to form silicon carbide sic and silicon dioxide
andrew-mc [135]

The question is incomplete, here is the complete question:

Silicon reacts with carbon dioxide to form silicon carbide and silicon dioxide. Write the balanced chemical equation.

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the reaction of silicon and carbon dioxide follows:

2Si+CO_2\rightarrow SiC+SiO_2

By Stoichiometry of the reaction:

2 moles of silicon reacts with 1 mole of carbon dioxide gas to produce 1 mole of silicon carbide and 1 mole of silicon dioxide

Hence, the balanced chemical equation is written above.

5 0
3 years ago
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