Answer:
a one bucket with full of sand because of it's mass which plays role in momentum
Answer:
<h2>the ans...is dc circuit...</h2>
Answer:
The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N
Explanation:
Forces on block 4.3 kg are:
63N to the right and R21 (contact force from the 6.3 kg block) to the left
Net force on 4.3 kg block is: 63 N - R21
Forces on the 6.3 kg block are:
R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.
So net force on the 6.3 kg block is: R12 - 11 N
According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").
Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:
a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2
solve for R by cross multiplication
6.3 (63 - R) = 4.3 (R - 11)
396.9 - 6.3 R = 4.3 R - 47.3
369.9 + 47.3 = 10.6 R
444.2 = 10.6 R
R = 444.2 / 10.6
R = 41.90 N
Answer:
0m/s²
Explanation:
A body with a constant speed always has a zero acceleration
Hence if Korey ran around the track at 10 meters per second and had a constant speed and did not change directions, then his acceleration will be 0m/s² not considering his initial speed
Answer:
w = 
v l
Explanation:
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
L₀ = m v l
Final moment. After the collision with the clay stuck to the rod
L_f = I_{total} w
angular momentum is conserved
L₀ = L_f
m v l = I_total w
w = 
v l
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
I_rod = I R²
I_total = m l² + IR²
we substitute
w = v l
