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Ann [662]
3 years ago
8

Whats the simple answer and simple way to solve answer to x -- 2/7=6/7

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
Add 2/7 to both sides

x = 6/7 + 2/7

simplify 6/7 + 2/7 to 8/7

Answer: x = 8/7 so 8/7 - 2/7 = 6/7 is true.
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Use the Side-Splitter Theorem to find x given that NQ is parallel to OP.
In-s [12.5K]

Answer:

x = 7

Step-by-step explanation:

\frac{20}{30} =\frac{14}{14+x}

(20)(14+x)=(30)(14)

280+20x=420

20x=420-280

20x=140

x=140/20=7

Hope this helps

7 0
3 years ago
the height of a triangle is 9m less than its base. the area of the triangle is 56 m^2 find the length of the base (SHOW STEPS)
Veronika [31]
Hey there :)

We know the area formula of a triangle
\frac{1}{2} (base)(height)

We are given:
The area = 56 m²
The base = let p represent this
The height = 9 m less than the base = p - 9

Apply the formula
56 = \frac{1}{2} × ( p ) × ( p - 9 )
56 = \frac{1}{2} × ( p² - 9p )

Divide \frac{1}{2} on both sides
56 ÷ \frac{1}{2} = p² - 9p
112 = p² - 9p

Bring 112 to the other side and equate equation to 0
p² - 9p - 112

Factorise { Sum = -9 , Product = - 112 , therefore suitable factors = - 16 × 7 )
( p - 16 )( p + 7 ) = 0
     ↓          ↓
 p = 16    p = - 7  ←  Reject p = - 7 since length cannot be negative

So, the length  of the base is 16 m

Check:
56 m² = \frac{1}{2} × 16 × ( 16 - 9 )
56 m² = 8 × 7
56 m² = 56 m²
7 0
3 years ago
Help Asap Pls Hurry I Will Give Brainliest!
dexar [7]
The answer is B
step by step explanation:
4 0
3 years ago
Read 2 more answers
X- 14x + 40
Vinil7 [7]
The answer is : B. (X-10)(x-4)
5 0
4 years ago
Read 2 more answers
Can two box plots have the same range and iqr and yet represent completely diff data.. explain
Mila [183]
Yes it is possible. Consider the following scenarios

Scenario A: 
Min = 5
Q1 = 10
Median = 12
Q3 = 18
Max = 22

The IQR is equal to the difference of Q3 and Q1
IQR = Q3-Q1 = 18-10 = 8
The range is the difference of the min and max
Range = Max - Min = 22 - 5 = 17

So in summary for scenario A, we have
IQR = 8
Range = 17

----------------------------------------------------------

Now consider another scenario, call it scenario B, where

Min = 100
Q1 = 102
Median = 105
Q3 = 110
Max = 117

I claim that the IQR and Range for scenario B is going to be the same as in Scenario A. Let's find out

IQR = Q3 - Q1 = 110 - 102 = 8
Range = Max - Min = 117 - 100 = 17

So
IQR = 8
Range = 17
which is identical to scenario A. 

-------------------------------------------------------------------------------

Scenario B has completely different data than scenario A, yet the IQR and Range are equal to scenario A's counterparts. This shows that it is possible to have 2 completely sets of data yet have the same IQR and range. 

The wrap up here, and the answer to the question, is "yes it is possible" with the explanation given above.
4 0
3 years ago
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