Both A and C would be solutions to the equation.
In order to solve for this you must first get the equation equal to 0.
2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)
Now we can plug these values into the quadratic equation.





or -1/2 for the first answer

or -2 for the second answer
Answer:
(2,4)
Step-by-step explanation:
The solution for the system is where the two lines intersect.
The two lines intersect at x = 2 and y =4
(2,4)
18+11v=w-13t
18+11-w=-13t
13t=w-11v-18
t=1/13w - 11/13v - 1 5/13
Hope this helps :)
Since I don't see attachment, I guess the solution will be as follows:
1 & 3/4 , since 1 = 4/4, then it could be rewritten :
4/4 & 3/4, hence between these 2 fraction there is 2/4 or 1/2.