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siniylev [52]
3 years ago
15

The driving force behind an efficient supply chain is __________.

Physics
1 answer:
Doss [256]3 years ago
5 0
Customer satisfaction is considered to be the "driving force" in order to achieve an efficient supply chain. An efficient supply chain takes place when the organization, or the company itself, meets with the demands of the consumers to improve and provides services that satisfies the people.
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A ball of mass m and weight mg is held at rest by two strings. One string makes an angle θ with the vertical. The other is horiz
malfutka [58]

Answer:

W = M g          weight of ball

T cos θ  = W         balancing vertical forces

T sin θ = F            balancing horizontal forces

tan θ = F / W        dividing equations

F = W tan θ          when θ equals zero F equals zero

6 0
1 year ago
How does the change in the sa/v ratio compare with the change in distance from the center of the cell to the nearest face?
Ivanshal [37]
<span>Answer: I'm pretty sure the SA / V ratio would get smaller. Assume that the cell is more or less spherical. SA = 4(pi)r^2, while V = (3/4)(pi)r^3. The ratio = (4(pi)r^2)/((3/4)(pi)r^3), which can be simplified to 3/r. Thus, the larger r gets, the smaller the ratio becomes.</span>
3 0
3 years ago
Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t
storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

T=2\pi\sqrt{\frac{I}{K}}

I=mR^{2}

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}

As dimensions of new balance wheel are one-third of their original values

R_{new}=\frac{R}{3}

\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega

5 0
3 years ago
A .025 kg bullet is moving at 350 m/s when it hits and then passes through a 7 kg block of wood. After the bullet passes through
slamgirl [31]

Answer:

The final velocity of the wooden block is equal to 1.035 m/s

Explanation:

Given that mass of bullet = m_{b} = 0.025kg

                Mass of wood = m_{w} = 7kg

               Initial velocity of bullet = u_{b} = 350m/s

              Final velocity of bullet = v_{b} = 60m/s

               Initial velocity of wood = o

               Final velocity of wood = v_{w]

   Here momentum is conserved so initial momentum = final momentum

            m_{b}u_{b} = m_{b} v_{b} + m_{w}v_{w} .

    Upon substituting these values in above equation , we get

        v_{w} = 1.035m/s.

7 0
3 years ago
3. A penguin waddles 8 m uphill before sliding back down to its friends in 2 seconds. If the penguin ends where it started, what
german

The velocity of penguin as he ends where he started was 0 m/s.

<h3>What is displacement?</h3>

Displacement is the length of straight line joining the initial and final position of the body.

Given is a penguin who waddled 8 m uphill before sliding back down to its friends in 2 seconds.

We know that the velocity is the rate of change of displacement with respect to time. Mathematically -

v = dx/dt

dx = v dt

∫dx = ∫v dt

Δx = vΔt

v = Δx/Δt

Now, the displacement of the penguin will be = Δx = 8 - 8 = 0

Then, its velocity will be -

v = 0/Δt = 0

Therefore, the velocity of penguin as he ends where he started was 0 m/s.

To solve more questions on kinematics, visit the link below-

brainly.com/question/27200847

#SPJ1

4 0
1 year ago
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