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4 years ago

9

Is it possible to accelerate while moving constant speed

1 answer:

marusya05 [52]4 years ago

3 0

Answer:

Explanation:

An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.

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Would u rather/ be a super hero. or super villian.

antiseptic1488 [7]

Answer:

A super hero because most people hate villains and I don't wanna be hated :)

4 0

3 years ago

Read 2 more answers

A man pushes a box along a flat, frictionless surface using a force of 500 N. The box was moved a distance of 2.5 m. The actual

andrey2020 [161]

Answer:

Workdone = 1250Nm

Explanation:

<u>Given the following data;</u>

Force, F = 500N

Distance, d = 2.5m

Workdone is given by the formula;

$Workdone = force * distance$

Substituting into the equation, we have

$Workdone = 500 * 2.5$

Workdone = 1250Nm

Therefore, the actual work done by the worker is 1250 Newton-meter.

4 0

3 years ago

A(n) 10.7 g bullet is shot into a(n) 4588 g wooden block standing on a frictionless surface. The block, with the bullet in it, a

Goryan [66]

Answer:

v = 747.83 m/s

Explanation:

given,

mass of bullet, m = 10.7 g

= 0.0107 Kg

mass of the wooden plank, M = 4588 g = 4.588 Kg

speed of the block and the bullet together, V = 1.74 m/s

initial speed of the plank = 0 m/s

using conservation of momentum

m v + M u = ( M + m ) V

0.0107 x v + 0 = (4.588 + 0.0107) x 1.74

0.0107 v = 8

v = 747.83 m/s

now, speed of the bullet is equal to 747.83 m/s.

5 0

4 years ago

The human body stores chemical energy from digested food. Some of the chemical energy is converted into mechanical energy when t

Mariana [72]

The 3rd option is corrected

5 0

3 years ago

The bus, at location A, is traveling at 30 m/s when it is shifted to neutral and allowed to

sertanlavr [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity of the bus at B is $v_B= 31.6\ m/s$

Explanation:

Let's take position B as base point .

From the diagram height between point B and A ia mathematically evaluated as

$h_A = 60 -55$

$h_A = 5 \ m$

From the question we are told that

The velocity at location A is $v_A = 30 m/s$

According the law of conservation of energy

$PE_A + KE_A = KE_B$

Where $PE_A$ is the potential energy at A which is mathematically represented as

$PE_A = mgh_A$

$KE_A$ is the kinetic energy energy at A which is mathematically represented as

$KE_A = \frac{1}{2} mv^2_A$

$KE_B$ is the kinetic energy at A which is mathematically represented as

$KE_B = \frac{1}{2} mv_B^2$

Where $v_B$ is the velocity at location B

So

$mgh_A + \frac{1}{2} mv_A^2 = \frac{1}{2} mv_B^2$

Making $v_B$ the subject of the formula

$v_B= \sqrt{\frac{gh_A + \frac{1}{2} v_A^2 }{0.5} }$

Substituting values

$v_B= \sqrt{\frac{(9.8 * 5) + \frac{1}{2} 30^2 }{0.5} }$

$v_B= 31.6\ m/s$

7 0

4 years ago