Answer:
E₁ = 1.042 eV
E₄₋₃= 7.29 eV
E₄₋₂= 12.50 eV
E₄₋₁= 15.63 eV
E₃₋₂= 5.21eV
E₃₋₁= 8.34eV
E₂₋₁= 3.13eV
Explanation:
The energy in an infinite square-well potential is giving by:
<em>where, h: Planck constant = 6.62x10⁻³⁴J.s, n: is the energy state, m: mass of the electron and L: widht of the square-well potential </em>
<u>The energy of the electron in the ground state, </u><u>n = 1</u><u>, is: </u>
The photon energies that are emitted as the electron jumps to the ground state is the difference between the states:





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Answer:
The current flows through the insulator is 2 mA.
Explanation:
Given that,
Resistance 
Voltage = 200 kV
We need to calculate the current
Using ohm's law


Where, I = current
V = voltage
R = resistance
Put the value into the formula



Hence, The current flows through the insulator is 2 mA.
The key feature in the experimental study is C. <span>The treatment in the experiment must be applied to each of the individuals in the experimental group. This is because it is made sure that the variables and conditions in different correspondents are applied so that actual results may be concluded.</span>
Answer:
Explanation:
Inductance L = 1.4 x 10⁻³ H
Capacitance C = 1 x 10⁻⁶ F
a )
current I = 14 .0 t
dI / dt = 14
voltage across inductor
= L dI / dt
= 1.4 x 10⁻³ x 14
= 19.6 x 10⁻³ V
= 19.6 mV
It does not depend upon time because it is constant at 19.6 mV.
b )
Voltage across capacitor
V = ∫ dq / C
= 1 / C ∫ I dt
= 1 / C ∫ 14 t dt
1 / C x 14 t² / 2
= 7 t² / C
= 7 t² / 1 x 10⁻⁶
c ) Let after time t energy stored in capacitor becomes equal the energy stored in capacitance
energy stored in inductor
= 1/2 L I²
energy stored in capacitor
= 1/2 CV²
After time t
1/2 L I² = 1/2 CV²
L I² = CV²
L x ( 14 t )² = C x ( 7 t² / C )²
L x 196 t² = 49 t⁴ / C
t² = CL x 196 / 49
t = 74.8 μ s
After 74.8 μ s energy stored in capacitor exceeds that of inductor.
the answer is 1 because a single pulley has 1 rope