Answer:
$\left(-4,-2\right)$ , $\left(4,-2\right)$ , $\left(4,4\right)$ , and $\left(-4,4\r the perimeter and the area of the secret chamber
Step-by-step explanation:
The answer and process is shown in the following picture
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
Answer:

Step-by-step explanation:
First problem. If you want a parallel to a given line, you keep the slope.
Then we use the point-slope form of a line
and we plug in there everything we need.

The second is quite similar. This time we want the perpendicular. It means that the product of the slopes has to be -1.

At this point we have everything, let's replace and write down the line in a better looking form
